It's a Question of your Career!

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Hello

According to your percentile and considering your home state to be West Bengal, you have chances to get admission in Electrical Engineering, Mechanical Engineering in Ghani Khan Choudhury Institute of Engineering And Technology, Malda.

You can have admission chances in other colleges also. Use the JEE Main College Predictor

Hello Aspirant,

It would be difficult to provide you the exact information but this score seems not enough to qualify the exam or get a seat in NITs, IIITs & GFTIs.

You can go for the state level counseling. To know the admission possibilities in state level counseling you can

Hi there,

You can get an approximate rank using this formula 100 - total score multiplied by 869010/100. It is difficult to predict exact score or collages and if the number of candidates are increasing in April session,  multiply it by 1200000/100.

Your predicted rank is 1,22,357.

Some of the

Hello Aspirant,

The exact prediction would be tough your rank.

869010 candidates appeared for JEE Main January session 2020. Using the formula given below

(100-your total percentile) X 869010/100

Your probable rank will be 382364.

Good Luck!

Heyy aspirant

Although the cutoff is not officially out for this year but you can analyze the cutoff given by some private institutions I will provide the link below .as well as you can also Google some previous years cutoff for each category.

https://engineering.careers360.com/articles/jee-main-cutoff

Hope this helps .

Hi Meena,

For 2020 total there are 9 states that are providing seat for secondary dnb for obstetrics and gynaecology. In this I am mentioning the total number of seats.

CHHATTISGARH: 2

DELHI: 3

HARYANA: 1

KARNATAKA: 5

KERALA: 1

MAHARASHTRA: 2

TAMIL NADU: 1

TELANGANA: 1

WEST BENGAL: 3

It’s difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 -