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Hello
It would be difficult to calculate the marks using the percentile score. Calculation of the exact rank is also tough. However, we can calculate the probable rank using the formula mentioned below-
100 - your total percentile score is the percentage of people ahead of you. 869010 are the
Hi there,
The qualification of Jee mains is dependent on some criteria
In 2019 , in Jee mains the cut off for SC category was 54.01%. so with 65 % in
Arun, your qualification code will be 02. This is because even if you haven't completed your B.Sc 2nd sem, the highest qualification in which you had Physics, Chemistry and Biology is your 12th and hence your code will be 02. Code 02 says: The Higher/Senior Secondary Examination or the Indian
IIT Bombay has introduced certain changes in the exam pattern this year onward. The paper is divided into two parts- part A and Part B.
Part B includes the following type of questions:
Hello,
In case of the above doubt the you can directly contact the helpdesk via email or the contact number that is given on the official website https://www.iimb.ac.in/pgpba-admissions and wait for their response.
I recommend you to send them an email of 'grievance or query' from your registered email id
According to your rank, chances are less to get a seat in government colleges through All India Quota. You can get a seat through management quota in JSS Dental College and Hospital, Mysore, Institute of Dental Sciences and other colleges also.
Use the NEET MDS College Predictor Tool to
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 19118. You can use our College predictor to predict your colleges: https://engineering.careers360.com/jee-main-college-predictor?
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