It's a Question of your Career!

Hello Aspirant,

Your query is incomplete. Kindly specify more your query what do you want to know so that you can get answer of your query.

Good Luck!

hello syed...

nta has not released the cutoff percentile for the jee mains 2020 till now.as per the previous years cutoff and result analysis a general category student should have a alteast 85 percentile to qualify for the jee advanced examination.

still if you need to know your percentile which

hi,

see data science is totally a different field from mechanical engineering and you need to start freshly . first of all you have to get basic understanding of probability and statistics, then learn python and r programming. there is many data analytics tools are available like power BI ,

HI Kishore,

99.65 is an extremely good score to secure in the JEE-Mains 2020 January session. out of the January and April session, your best score will be counted. If you feel like you can top your January score, you can go for the April attempt.

Your expected rank for

1. For board toppers- They can avail 100% merit scholarship.
2. Merit in qualifying Exam- 20% scholarship for 90% and above marks. 15% scholarship for 70-80% marks.
3. Merit in BITSAT-

• 300 or above 75% of Tuition fee
• 250-299 50% of Tuition

hello,

You should have atleast 75% aggregate marks in boards to be eligible for JEE Main and Advanced . You basically need not to worry about percentage because if you study for JEE Main properly , you can easily score good percentage in boards  You can also have a look

Dear Swaggy,

Yes, there are number of scholarship test after passing class 12th. Some of them are :

* INSPIRE scholarship

* PM Narendra Modi scholarship

* National Scholarship Test

* Schindler Igniting Minds Scholarship

* AICTE Scholarship for girls.

Some of the scholarship that have major significant and can

hello suhani..

your rank can be predicted using the following way..

It’s difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula

the percentile is the measurement of knowing the number of student ahead of you or below your score. 869010

Hi Aspirant,

As your score in the JEE-Mains 2020 January session is 61.25 percentile, your expected rank can be calculated using this formula:

((100- your percentile) x 869010)/100

Your expected rank comes up to about 3,36,741. As the top 2,50,000 will get selected for JEE-Advanced and your rank is expected