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184 Views

Estimated marks required on NEET to become part of this collage

Yash Dev Student Expert 26th Feb, 2020

Hello student its difficult to predict exact cut off as its vary every year on various situations like the level of question in the entrance examination and the total number of applicants in that examination. Still try to score minimum 600+ marks to stay in a safe side as we

54 Views

I got 95.167 percentile will get seat

ruchika.chauhan Expert 18th Jan, 2020

Hello

It would be difficult to predict the exact JEE Main rank, however, your probable rank would be around 41999.
The rank has been calculated using the rank formula mentioned below-

(100 - your total score) X 869010 /100

Based on this rank, you might have chances to get a

47 Views

sir my percentile for 70 marks in 2020 ,8 th second shift

Pachigolla Hemanth 17th Jan, 2020

Hello Prameela pothireddy,

If you got 70 marks in JEE mains exam ,then the percentile you may get is the overall percentile is  90.5 - 90.7 under general category .For more details once go through the rank/percentile predictor which is available in the below link.,

https://engineering.careers360.com/jee-main-rank-predictor

Hope this helps you..

63 Views

What is mit in usa ?? how i can apply

Prakarsh Kaushik 26th Feb, 2020

Hello,

The Massachusetts Institute of Technology (MIT) is a private university in Cambridge, Massachusetts USA. Established in 1861 in reaction to the increasing industrialization of the United States of America, MIT adopted a European polytechnic university model and stressed laboratory education in engineering and applied science.

The institute is conventionally

4161 Views

67 nta score in jee means what

Vikas gehlot 17th Jan, 2020

If you got 67 percentile score then it means that out of all the students appeared for the exam 67% student are behind you and the rest 33% is  ahead of you.

This time the number of student appeared for the exam is 869010 so 67% of it that is

42 Views

sir, Im student of b.sc(program) 3rd year student. so I can apply for mass communication (PG) under Banaras Hindu University (Varanasi)

Manidipa Kundu Student Expert 26th Feb, 2020

hi,

yes , you are eligible to apply for bhu pet for m.a in mass communication course.

the basic eligibility criteria is candidate must pass graduation degree in any discipline with 50% marks in graduation course from a recognized university.

for sc/st candidates they need to have the pass marks

164 Views

my nta score is 72.07 in jee mains btech.. am i eligible to get admissionin nit?

Mayank Sinha 17th Jan, 2020
Hello there,

At 72.07 percentile your expected rank will be around 2,42,700-2,62,700.
At this rank it will not be possible for you to get a seat in the Nits if you belong to general category.
However if you are from any reserved category then it might help a bit but
198 Views

what is the expected percentile cutoff for jee main 2020 jan attempt?

Pratham Meghani 17th Jan, 2020
Dear Aspirant,

According to last year cutoff trend the cutoff for Qualifying Jee mains for general category was 89.75.This year also if you get percentile above 85 then you have chances to qualify for Jee mains
but if you want to get admiited in good nit then you need rank
31 Views

I got 47 percentile in 7th jan shift 2 .Iam OBC central list .Does I qualify In the exam

ruchika.chauhan Expert 17th Jan, 2020

Hello

With 47 percentile in the JEE Main exam, it would be difficult to qualify for the JEE Advanced exam. 85+ percentile score is expected to be the decent score to qualify for JEE Advanced.

You still have april session. You can prepare well and appear for the JEE Main

35 Views

Hi I got 94.954 percentile in january mains.(9th jan shift 1) I belong to OBC-NCL category. What will be expected rank and raw score?

ruchika.chauhan Expert 17th Jan, 2020

Hello

It’s difficult to predict actual rank, however, by using the formula mentioned below


100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam.

So rank formula is (100 - your total score) X 869010 /100.


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