It's a Question of your Career!

Hi there,

For getting into PG course in JNU you have to appear for their entrance exam JNUEE. For more details regarding it you can refer this link:

https://university.careers360.com/articles/jnu-admission

For St. Joseph's Degree and PG College you can refer these links: https://josephscollege.ac.in/admissions/

https://josephscollege.ac.in/admissions/admission-procedure/

Neeta, while the provisional result for NTSE stage 1 for Gujarat has already been released by SCERT Gujarat along with the answer key on 8 November, the final result is scheduled to be released in January 2020 on their official website: http://sebexam.org/

The final result will be in the form

Hi dear,

You have got 72 percentile in JEE main that means your rank should be around 243322. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

You can check cutoff and other details here

https://www.google.co.in/url?q=https://www.careers360.com/colleges/vivekanand-education-societys-institute-of-technology-chembur/cut-off&sa=U&ved=2ahUKEwjq9erAtJbnAhV0IbcAHfoVARwQFjADegQIBxAB&usg=AOvVaw3figSTsqeTEIQlNTkFu6cd

Hope it helps.

Hello aspirant

The basicity of an amine in aqueous solution depends upon the stability of the ammonium cation which further depends on a combination of three factors i.e steric hindernace of alkyl groups,+inductive effect of alkyl group and extent of hydrogen bonding with water molecules.

Therefore the order slightly differs

Hello,

This year National testing agency has given percentile not marks in the result. So the total score that you see in the score card is your percentile. If you want to calculate your approximate rank you can use the below formulae

100 - your total percentile score is the

Hi dear,

You have got 85 percentile in JEE main that means your rank should be around 130351. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

According to last year trend your ews rank will be around 14k. This is quite low for NITs. Hope it helps

Your code will be 03 if you studied your 12th in Karnataka. But if you studied your 12th in any other State, your code will be 02. Code 02 says: The Higher/Senior Secondary Examination or the Indian School Certificate Examination which is equivalent to 10+2 Higher/Senior Secondary Examination after a

Hi dear,

You have got 84.6 percentile in JEE main that means your rank should be around 132k. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

This is quite low for NITs. Yes, you can prepare and crack jee main 2020. Learn from your mistake which you have done

Hello Aspirant,

Kindly mention here the particular college or University, you are asking about B.tech admission.

Good Luck!