It's a Question of your Career!

Hey

Go to the website cee.kerala. gov.in.

Select keam candidate portal

Towards the left side you can see "Last rank 2019"

Check there

Hope my ans helps

Hii

First let me calculate your rank by this formula-

(100- percentile)*number of students appeared/100

That lies in 28000-37500

for JMI cut off I can only find the marks range at which you can get admission there. In 2017 it was about 200+ to 170-150+ for general and 150+ for

Hi,

Well I would like to tell you that AIIMS does not take admission on the basis of NEET score. Any AIIMS does not take admission on the neet score. Aiims has its own entrance exam where students register and qualify to get a seat.

I hope my answer helps.

Hello,

It is quite difficult to tell if it is general merit rank or category rank as you have not mentioned for which course the cut off is and we don't know the source from where you saw the cut off.But we can help you with the 2019 cut off

Hi,

Well I am assuming that bvsc is bachelor in vocational sciences. Well then the admission is on the basis of NEET score only cause all the medical courses will take admission on the basis of NEET score only and that goes for all ayurvedic medicine, homeopathic medicine, Unani medicine

National Institute of Technology (NIT) Warangal offers a two-year, full time MBA programme at the postgraduate level through its School of Management. The institute accepts CAT / MAT/ GMAT scores and percentile for admission followed by the group discussion and Personal Interview process.

The learning takes place through well-balanced mix

Hello

According to your NEET PG score, expected rank would be around 15742 - 16242.
As per your rank, you have chances to get a seat in
Biochemistry, Physiology in Madras Medical College, Chennai
Community Medicine, Microbiology in Seth GS Medical College

Check your other admission chances using the NEET

Hii

For NIT calicut at HS the OBC closing rank was as follow-

Electronics and communication-4809

Last one- Material science engineering-13829

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut

For your percentile of 93.8, your general rank may be calculated by

(100- percentile)*number of students appeared/100 - = 54000-74400. Your obc rank will be one third or

Hello kritika

The same problem has mine also when I give the exam in 2018 and the talking about the problem i cant say for sure that they will evaluate this problem  at that time I will msg the authority personally so he's reply me and also resolve my problem