It's a Question of your Career!

Dear Aspirant

you have taken a very challenging decision.It sounds a bit tough but you can make it out by following some tips

-Firstly you should know the complete syllabus in detail.

-Make a time table covering every chapter,you have a very less time so you must include more topics

Hi Swasti,

There are total 7 Government Engineering colleges in Pune namely:-

• College of Engineering, Pune
• Government Polytechnic, Pune
• Defence Institute of Advanced Technology, Pune
• Savitribai Phule Pune University, Pune
• Bharati Vidyapeeth College of Architecture, Pune
• National Institute of Construction Management and Research, Pune

Totally i.e. including private and government

Dear Aspirant

The 4 years of pharmacy course will have 8 semesters with 25 subjects.some of them are very important like Human Anatomy and physiology,Pharmaceutical chemistry which are subdivided into some other subjects.so you must concentrate very well to obtain a good score.For that you need to follow some steps

hello aspirant

Legal maxims are a thing to be mugged up. There are few tricks you can apply to make this little easy. There are at least 4-5 questions in CLAT which are related to Legal Maxims and therefore it is not important to know all the legal maxims for

Yes Shashi, Monad University is a government recognized university. It is a state private university established by the Uttar Pradesh State Govt. Act 23 of 2010 & U/S 2 (f) of 1956.

Established in 2010, the university is affiliated to UGC. A  letter of authorization from the Government of Uttar

Hello,

On monochlorination of 2 - methylbutane, total four isomers are produced:

1. 2-chloro-2-methylbutane
2. 2-chloro-3-methylbutane
3. 1-chloro-2-methylbutane
4. 2-chloro-3-methylbutane

Out of the above produced isomers, 1 - chloro-2-methylbutane and 2-chloro-3-methylbutane are the chiral compounds and rest are the achiral compounds.

So, total 2 chiral compounds are produced.

Best Wishes.

Hi Candidate,

The the ter minal velocity formula , v = the square root of ((2*m*g)/(ρ*A*C)). Here are two spheres of radii r and 2r, so the new spherical radius is-

R.R.R = r.r.r + 2r.2r.2r = 9r.r.r, So the value of R equals cube root of 9. Hence, the