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141 Views

with 85_100 marks in jee mains will I get any nit college I am obc

NAVNEET PANDEY 11th Jan, 2020

Hello gautam

You need to score atleast more than 100 marks then you can get a NIT and if you score more than 130+ you can get computer science in north east NITs may be in spot round, or you can get a good bran of engineering with these marks.

69 Views

By which Exam CMC Vellore take MBBS students?

Atharva Thakare 20th Feb, 2020

The admissions in CMC vellore is on the basis of NEET scores and the exam conducted by the institution. 100 seats are available for MBBS students out of most of the seats are reserved for Christian students so if you are not Christian then you have to score really high

58 Views

which is the best collage . That can be admission by wb jee

L RESHMASREE 11th Jan, 2020

Best Engineering colleges in West Bengal in which you can get admitted through WBJEE score are :-

  • Indian Institute of Science Education and Research (IISER), Kolkata
  • Jadavpur University, Kolkata
  • Indian Institute of Engineering Science and Technology (IIEST), Shibpur
  • Kalyani Government Engineering College (KGEC)
  • Institute of Engineering and Management (IEM), Kolkata
50 Views

admission process in IP university

Suryashis Chakraborty 20th Feb, 2020

Hello Pankaj,

The Guru Gobind Singh Indraprastha University offers UG, PG and PhD programmes in around 300 courses over 15 streams.

The admission process varies according to the stream a candidate wishes to apply.

The process of admission begins in the month of March and concludes by the end of

45 Views

Is there MA.Sociology course at SV.University Tirupati for regular not a distance course...& am completed Engineering should I eligible to do MA Sociology....???

pdwords Student Expert 20th Feb, 2020

Hello,

Sri Vebkateswara University, DDE does offers MA in Sociology and eligibility criteria is candidate needs to have passed Bachelor's degree from a recognized university. There is no such mention of any discipline or any aggregate regarding this matter. So, you can go ahead for MA Sociology in SVU DDE.

56 Views

i got 107 in jan 8th 2020 shift 2 what percentile can i expect??

LAKSHMI AMBIKA 11th Jan, 2020

Hello Parameshwar reddy,

you can expect 94.2% as per the previous records. as the NTA which conducts the JEE mains didnot revealed the Normalisation process. but as per the previous records your percentile can be 94.2% and it can vary.

you can refer to this link for more info:

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile/amp



85 Views

Bhu examinatio 2020 how can I prepare for it??

Hello,

BHU is one of the Renowned central universities located in Varanasi, UP.

You should make a proper time table which cover all the topics coming in entrance test.

You should have to prepare notes for it, and attempt mock tests, solve sample papers and practice it regularly. Solving past

328 Views

What is the SI unit of frequency

Indrajit Gupta 11th Jan, 2020
Hello santosh,
The SI unit of frequency is hertz. One hertz means an event repeat once per second. It is denoted by symbol Hz.
I hope this helpful for you.
Best wishes!!
34 Views

sir kay 12th wale ko assessment dena h kisi vi sub. ka kay ....... plz anyone reply it ??

Anamika Tiwari 9th Feb, 2020

Dear Manish,

Yes , it's important to submit all the assignments of class 12th. As, Internals are given to students by the school teachers only. So in order to have good internal marks in practical as well, you need to submit all of your assignment of all subject in proper

398 Views

if the length of the day is T the height of that t.v. satellite above the earth surface which always appears stationary from earth will be

Masira 14th Jan, 2020

Hello,

Since the satellite is stationary, it has same angular velocity as that of earth.

Thus \omega=\dfrac{2\pi}{T}=\dfrac{v}{r}ω=T2π=rv


\implies v=\dfrac{2\pi r}{T}v=T2πr

The centripetal acceleration arises from the gravitational force earth exerts on satellite.

\implies \dfrac{mv^2}{r}=\dfrac{GMm}{r^2}rmv2=r2GMm


Eliminating vv from above equations gives

r=(\dfrac{GMT^2}{4\pi ^2})^{1/3}r=(4π2GMT2)1/3

Hope this helps, Good Luck.

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