It's a Question of your Career!

Hey!

As we know,

Vx(velocity in x direction) =10cos60 =5m/s

Vy (velocity in y direction) =10cos30 =53m/s

Velocity after t=1 second

Vx=5m/s (velocity in x direction will remain same)

Vy=(5sqrt3−10) m/s =10−5sqrt3

An=(v^2)/R

Which means

R = (Vx^2+Vy^2) /An

Which means R is (25+100+75−100sqrt3) / 10Cosθ

tanθ=(10−5sqrt3) /5

tanθ=2−sqrt3

θ=15

First of all you need to write an entrance examination like Jee mains, jee advance, cet, comedk, bits, etc. And also you need good percentage in your Pcm and also English subject in your boards as per the eligibility criteria of these exams. And then as per your merit score

Dear Aspirant,

We hope you have already registered for the NRTI Online Examination and if you have not done so, it is still available till 13/06/2020. With the current Covid situation, you will be notified of the rescheduling but make sure you are registered first, as sometimes the websites are

Hello dear

If 53 is your percentile score and you do not belong to ST or pwd category than it is not possible for you to give jee advanced according to last year trend.

You need to qualify the jee mains with a good percentile and if you are from

Dear Aspirant,

As per the official information brochure of the AFMC, if the student have problem in the speech, he is not eligible for the AFMC.

According to the rule 3.(b) of the official infomation brochure:-

There should be no impediment of speech.

Hope this helps. Thank you.

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Dear Aspirant,

As per the official information brochure of the AFMC, if the student have problem in the speech, he is not eligible for the AFMC.

According to the rule 3.(b) of the official infomation brochure:-

There should be no impediment of speech.

Hope this helps. Thank you.

Hello,

In 2019 the cut off was as follows for JNTU, Hyderabad for SC category

• EEE: 11617
• ECE: 8621

CBIT

• ECE: 10741
• EEE: 16778

Considering this you need to secure rank within 20,000. So to secure such rank you need to score 80-90 marks and you must have 550 or