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Hello aspirant,

Formula: tn= a+ (n-1)d

Now,

t7= a+ (7-1)d

-4= a+ 6d --(1)

t13= a+ (13-1)d

-16 = a+ 12d -- (2)

we can write eqs 1 and 2 as,

eq 1: a+6d+4=0 and eq 2: a+12d+16=0

subtract (1) from (2) we get,

(a+12d+16)-(a+6d+4) = 0

Therefore,

6d +

Hello,

We need to know your category and the course you are interested in to help you with your query because cut off is different for each category and the course. So, please tell us if you are seeking admission in undergraduate or post graduate course and your category.

Hemanth, your All India Rank is approximately 66044 going by the formula 100-92.4*869010/100 where 92.4 is you rpercentile and 869010 is the no.of Candidates who appeared for January session. With this All India Rank, NITs or IIITs might be tad difficult. Going by the previous years data, you have chances

Dear,

There is no upper age limit. As you are a graduate then the criteria for you is-You must hold Graduation degree and have passed or appearing in final year of 2-year Diploma in Elementary Education or Graduation with at least 50% marks and passed or appearing in final year

Hey!

See, as given in question no quantity is dimensionless, but ln(BD) is a dimension less quantity as natural log has no dimensions.

Which means [A] [D] =[C]

And after checking a the options, we can conclude that c option that is (A-C) /D is not a meaningful quantity as

hi,

see attending school is also important, because if you do not have the required attendance percentage you may not allow to sit for board exam, however you need to make separate time schedule to study for board exam as well as prepare for neet, 12th exam is also very

Dear Aspirant,

Yes extra marks are awarded for arts quota students in 2020 ssc boards results.

Students securing A grade in the intermediate drawing examination will be award 15 marks, B and C graders get 10 and 5 marks.

These marks come under the arts quota. The last date for