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103 Views

how to crack NTSE, which books are best, and what is benifit of giving this Olympiad.

Mounika Sonti 6th May, 2020

hello!!!!!!

NTSE is a national exam conducted by NCERT to provide scholorship for the students.preparation is the key for this exam.you can prepare yourself through your board textbooks esepecially science textbook.you can also prepare by wrting online mocktests which are there in the internet. i recommend to study S.Chand books

46 Views

What is 9(2+2)? I want to know the method to solve this

Arshi Ahmed 30th Apr, 2020

hello aspirant

9(2+2)

9(4)

36

first you have to perform the operation inside the bracket followinf the bodmas rule.

53 Views

sir/mam. - I got 91.6 percentile with (S.C) as my caste in jan. attempt; can i expect nits and which type of course in b.tech is good for me?...

priyaankasarkar Student Expert 30th Apr, 2020

You haven't mentioned the State you belong to. This is important because Candidates with Home State have lesser cut offs than Outside State Candidates. That being said, this year approximately 869010 Candidates appeared for January JEE Mains session. And you can calculate your All India Rank by using the formula:

47 Views

Cse branch kya hai? what is its role in Our Daily life?

lakshita shaan 30th Apr, 2020

hey aryan,

Computer science engineering (CSE) is all about analysing of alogorithms ,programming languages, program design and computer hardware, generally a computer science engineer develops an application or software for industries , bugging debugging are also included in work of a computer science engineer , computer science engineer write code

99 Views

I get 83 percentile in JEE MAIN 2020 January. Can I take admission in computer science engineering in Delhi University Or NSIT Or Jawaharlal Neheru University Or any other university in Delhi?

Pritam Singh 9th Jun, 2020

Hey there

By coverting percentile into rank your rank will be around 150k and thus with this rank getting NSIT or DTU is not possible for general category. you can try other colleges or wait for july exam.

check the link

https://learn.careers360.com/knockout-jee-main-april/

good luck

111 Views

X^2+4x+2= Find Value of x? Jaldi Batao

Manidipa Kundu Student Expert 30th Apr, 2020

hi,

you need to apply sri dhar acharyas formula, which is

ax^2+ bx+c=0     ,...........1

x=(-b+root over(b^2- 4ac))/2,  (-b-root over(b^2- 4ac))/2   ............2

now comparing the equation 1 with your question you may get that

a=1, b=4, c=2

put the values on equation 2 you may get the answer.

hope you may

2254 Views

i got 485/600 what will be my 25% added to eamcet ? how many marks will be added to my total marks in eamcet?

priyaankasarkar Student Expert 9th May, 2020

The maximum marks that can be scored in EAMCET are 160. The weightage of these marks is 75% in EAMCET and the rest 25% weightage goes to marks scored in your 12th. The formula used to calculate this 25% is Your intermediate score*25/600. Then to calculate the actual contribution of

97 Views

What are the other exams that jee aspirants can attempt for the year 2021?

Arshi Ahmed 30th Apr, 2020

hello aspirant

well yes they also other state level entrance examinations and also they are other university examinations like SRM,VIT,MANIPAL university  and students can attend even those examinations.

682 Views

can we get admission in SRCC WITH APPLIED MATHS

Arshi Ahmed 30th Apr, 2020

hello aspirant

well no you cant get into SRCC if you dont have maths in your 12th standard  and SRCC offers 2 courses B.com (//B.com) and B.A(ECONOMICS).so it is necessary that the applicants have studied maths intheir 12th standard.

hope this info helps!

83 Views

I got 80 percentile in 2020 jee mains phase 1 and I belong to sc category and I am from telangana,so is there a chance to me to get a seat in any nit

priyaankasarkar Student Expert 30th Apr, 2020

Sharan, approximately 869010 Candidates appeared for January JEE Mains session. And you can calculate your All India Rank by using the formula:

100-your percentile*869010/100 where in 869010 is the no.of Candidates who appeared for the exam. This brings your All India Rank approximately to 173802. With this rank, it is

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