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Hello Aspirant,
You wanted yo apply second councelling for the mds course as your husband is a nri and you can apply for the second councelling being a nri also you have to have certain certificates whuch are mandatory for the councelling
You should claim the documents as you are
You can't get any top Institutes like IIT's or top NIT's. With this score it is difficult to get a state sponsored college. I know that cutoff changes every year but at this score it is really difficult. If you can get then please try for VSSUT, Sambalpur as i
hi,
see cutoff score changes every year and it depends on number of participants, questions difficulty level, seat matrix, candidates category etc. you did not mention your category, if you belongs to general category there is less chances for iits. however you may apply for north east nits, jadavpur university,
Dear Candidate,
You need to log in the official website of Christ University and go to the admission portal where you had registered for the entrance exam. There you have to log in with the credentials that you used while registration of the exam. Result will be reflected there and
Hey !
Computer based exams means the mode of conduct of exam is online. Like Kvpy (kishor vigyanik protsahan yojna), BITSAT is Computer based exam means it is conducted online.
The exams which are offline mode are paper pen based exams,example JEE Mains, IPUCET.
Thank you.
Hi,
Veer Bahadur Singh Purvanchal University provide 3 years bachelor of arts course. Here is the link for B.A syllabus
Ancient history -
http://vbspu.ac.in/wp-content/uploads/2016/01/1-B.-A.-Ancient-History.rtf
Political science - http://www.vbspu.ac.in/wp-content/uploads/2016/08/Political-Science.pdf
English literature-
http://www.vbspu.ac.in/wp-content/uploads/2016/08/BA-English.pdf
Hope this helps.
Hey!
Imagine you have two sets, set A(c corrdinates) and set B(y coordinates) .
Then, the set B is the co domain whether having any relation or not.
Whereas the values of set B which are having any specific relation with set A values, then those values will form Range.
Hello!!!
Hope you are doing great!!!
As per your question,the chemical equation will be as follows:
2Al+2NaoH+2H2O gives rise to 2NaAlO2+3H2
2*27gms of Al = 6gms of H2
0.15gms of Al = ?
weight of H2 produced = 0.15*6/2*27
= 1/60 gms of H2
By using Ideal gas equation,
PV=nRT
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