It's a Question of your Career!

1 Million+

Questions

50k +

Active Users

24hrs max.

Answering Time

Showing 911 - 920 out of 53415 Questions
356 Views

I scored 86.9 percentile in tancet 2020( Aerospace engineering stream) will I get Aerospace in MIT. pls answer

Sonali Sahu Student Expert 22nd Aug, 2020

Hello,

There is high possibility to get as your score is eligible for 1st tier college. Branch stream is assigned as per your UG degree stream. to get MTech in Aerospace, you have to be Btech/BE aerospace graduate. you can't opt for any other degree specialization stream.

You should apply

1200 Views

Is CSE in SRM will be better than ECE in VIT Chennai?

Palak kumari 22nd Aug, 2020

See, first you must decide that with which stream you are comfortable with because you won't end up your four years studying something which doesn't interests you.

If you want a high package placement and you are interested in coding then you must go with CSE.

But, if you want

198 Views

in life how many times we can give IIT

ADITYA KUMAR Student Expert 13th Jul, 2020

Hello

Admission in IITs is it through advanced examination , now to be eligible for writing JEE advanced you need to first qualify JEE Mains.

ATTEMPT LIMIT FOR JEE MAINS

One  can give JEE Mains entrance  examination  for a maximum of  3 consecutive years  starting from the year of passing

91 Views

result kab niklaga 10 class cbse board

Sharon Rose Student Expert 13th Jul, 2020

Hello,

CBSE class 10 results will be declared on July 15, 2020. Once the results are out you can check them through any of these links cbseresults.nic.in or cbse.nic.in (//indiaresults.com) (//examresults.net)

You need to click on class results portal and then enter your roll number, school number, center number and

67 Views

when is the 6th subject considered for aggregate and percentage

Sonali Sahu Student Expert 13th Jul, 2020

Hello,

Admission into different higher degree has different eligibility criteria.

  1. for course like BSc, BBA, BCom:- whole 12th percentage is taken into consideration
  2. for BA:- best 4 combination along with language paper in which candidate has otpted for admission like hindi, english is considered as one of the 4 best
44 Views

Is there any govt college apart from Delhi university in Noida - Ghaziabad which offer Bsc microbiology or Bsc biomedical science ?

NILUTPOL Student Expert 22nd Aug, 2020
Hello,
Here's a list of colleges in Delhi NCR which offer courses in Bsc Biotechnology and Bsc Biomedical Science
  • Shaheed Rajguru College of Applied Sciences for Women
  • Bhaskaracharya College of Applied Science
  • PDM University, Bhadurgarh
  • LPU Jalandhar
  • SGT University, Gurgaon
  • IMS - Ghaziabad, University Courses Campus
  • Amity University Noida
  • Swami
44 Views

can I get civil engineering seat in gogte college or Jain college and my cet ranking is 13709

Bairampally Shruthika 28th Aug, 2021

gogte collage doesnot provide civil engineering course and not

too good collage better go with another collage

72 Views

clat pg 2020 new pattern sample papers

Shivendra1 13th Jul, 2020



CLAT Sample Papers 2020 - The Consortium of National Law Universities has released the CLAT 2020 sample papers based on the new CLAT exam pattern. All sample papers of CLAT 2020 are given below in the article. Candidates can access the CLAT sample papers pdf at free of cost from

913 Views

how will private student get practical marks in maths and english subject as it is introduced in current year 2020? in my result nothing mentioned in that practical column even not any abbreviation. plz reply its important as my percentage is getting effected?

Utkarsh Tripathi 16th Jul, 2020

hello pranjal,

same problem m also facing. few months earlier before exam i went to the cbse regional office noida. Staff there told me that we all private candidate will get marks on the basis of our theory performance. 20% marks will be given of theory. means if u get

403 Views

in triangle ABC, 4CosACosB is equal to

Nikhitha Sai 22nd Aug, 2020

In a triangle ABC cos(A+B)= cosAcosB-sinAsinB. cos(A-B)= cosAcosB+sinAsinB.

there by, by adding these two and multiplying the result by 2 times you get the desired answer. 4cosAcosB = 2[cos(A+B) + cos (A-B)]. This can also be done by interchanging the signs and the answer will remain the same.

The question have been saved in answer later, you can access it from your profile anytime. Access now