It's a Question of your Career!

Hello Aspirant,

While DSCE gives you scope for more comprehensive and holistic development, BIT trumps DCSE in the academic sector with much better placement statistics. The average CTC offered during placements in BIT(2019) was 6.5 lakhs, and the maximum package was 13.5 lakhs. In comparison, DCSE recorded an average CTC

Hi,

No, neet exam is not must for admission to B.S program at iisc banglore. However if you want you can take admission through neet exam.

The admission at iisc banglore are taken through three channels-

1) kvpy exam

2)jee main /jee advance

3) Neet

if one wants to take

hi,

see delhi university is one of the best university in india. also 80+ colleges is under delhi university which offers different undergraduate course , however the cutoff score depends on certain factors like number of applicants, students category, choice of stream, seat matrix for any particular course in colleges

Hey!

Some of the top colleges under kcet are RV college of Engineering, Banglore, ms Ramaiah Institute of Technology and BMS college, Banglore. And with this rank you are eligible to get admission in any of these with yor desired branch. Som of the most preferred branches are cse, EEE,

Pune is considered as best location for Pursuing Management Studies in terms of placement opportunities, Quality of Education, Fee Structure and overall development of students. Based on this, there are number of good MBA colleges in PUNE among all these Institutions RIIM PUNE will be little ahead in comparison with

Hey!

Yes, definitely you can get admission in 2021 in engineering Colleges if you score good after drop year. You can also prepare for entrance exams such as jee mains, BITSAT etc to get admission in top engineering colleges of india. Also, you can give many attempts to these exams

Dear Aspirant

To solve your query, you should visit on below link

https://www.google.com/url?sa=t&source=web&rct=j&url=http://dhe.chd.gov.in/&ved=2ahUKEwjE_M6Ct67rAhVCjeYKHZEKCy0QFjARegQIBhAB&usg=AOvVaw0L5HKcZcorSbEuyk7CTRQk

Hope this link will help you

Thank you .