It's a Question of your Career!

Hello Aspirant,

According to your rank, category and previous year cut off their are many NIT or Government colleges with EEE branch are open for you here I listed some colleges based on your rank.

Nit Silchar

Nit Nagaland

IIIT Delhi

ICT Mumbai

Delhi Technical University.  etc...

You can use

Hii,

It is not easy to predict the rank on your marks. However I personaaly recommend you to use careers360 rank predictor for it. It will predict your rank on the same basis. Hope that the information shared to you is helpful. Wishing all the very best for your councelling.

Dear student,

You didn't mentioned the category you belong to so considering as General category.

For Admission in Government polytechnic lucknow in IT branch you should have rank in the range 518- 4000 according to the previous year data.

you can check previous year cutoffs using the link below-

https://admissions.nic.in/JEECUP/JEECUPCouns/Report/OpenCloseRankPreviousYear.aspx?boardId=129042021

Hello Bhavya!

Post Graduation Common Entrance Test (PG CET) is a state level entrance examination for post graduation courses such as MCA, MBA, ME, MTech. Assuming we are talking about Karnataka PG CET exam, there is the link to the page that has sample papers of PG CET along with

With a score of 560, your rank might be approximately between 19967-23501 . This is an expected rank range: https://medicine.careers360.com/articles/neet-result-marks-vs-rank . Now regarding the Colleges that you may have a shot at, you have a chance in:

• Amala Institute of Medical Sciences
• Periyaram Medical College
• Sree Gokulam Medical College

You

Hello Anshu!

According to various sources across internet the previous years(2018) cutoff in BHU PET exam for common M.A/M.Sc were 175 and 255 for Geography and Mathematics respectively for general category. So the cutoff marks for psychology might range somewhere between these two. So there might be a possibility for

Hello Aspirant,

I think there domain will be -1<x<1

Since value in sin-1 can only be between -1 and 1, we get the conditions

1. -1 < x < 1
2. -1/2 < x√1-x2 < 1/2

Taking case 2, square it. We get x2(1-x2) <1/4

Replace x2 with t. We get t2-t+1/4>0.

Hi Bharat,

The best government colleges of Punjab offering BPT course are listed below:-

• Punjabi University, Patiala
• Guru Nanak Dev University, Amritsar
• Baba Farid University of Health Sciences, Faridkot
• State Institute of Nursing and Paramedical Sciences, Badal

Refer here for more info - https://medicine.careers360.com/colleges/list-of-medical-colleges-in-india?state=Punjab&ownership=Public/Government&degree=B.P.T.

Feel free to ask doubts in

Hello Aspirant,

I think there domain will be -1<x<1

Since value in sin-1 can only be between -1 and 1, we get the conditions

1. -1 < x < 1
2. -1/2 < x√1-x2 < 1/2

Taking case 2, square it. We get x2(1-x2) <1/4

Replace x2 with t. We get t2-t+1/4>0.