It's a Question of your Career!

Hello,

Indian institute of engineering science and technology, Shibpur has 45th rank from careers360 and 21st rank by NIRF.

They have various branches in engineering like civil, cse, mechanical, IT, electrical, etc.

For engineering you need to give jee mains as entrance exam but other than that there is eligibility

Dear Student,

to give you the exact predictions of your rank would be quite difficult but as per the rankings of last year the rank for your corresponding score would be around the range of 114362.

If you would like to know your exact rank for your NEET score kindly

Sry .....u won't be getting category one fee....as only 28cse students can get over those....further 16seats are reserved for local.....and 12 fir non local.....350seats available in amrita cse....in that nearly 70seats are reserved for management quota...remaining 280seats are also reserved 70 percent on aeee and 30 percent on jee mains

Hello

The Percentile scores for the Total Raw Score for all the four sessions (Session-1: Day-1 Shift-1, Session2: Day-1 Shift-2, Session-3: Day-2 Shift-1 and Session-4: Day-2 Shift-2) calculated by formula would be merged and shall be called the NTA scores which will then be used for compilation of result and

Hello student,

As per the cutoff ranks, it is very hard and has very fewer chances to secure the seat from Anil Neerukonda Engineering College with the AP EAMCET rank of 80000. You can opt for management seat if you really wanna join that college or choose some other colleges.

Hello

Yes ,you can carry your cash with out wallet .you can just put the notes in your pocket .They allow since students come from many places by transport usually they have lay for transport so they will definitely allow you to carry your cash only not your wallet .

Let (h,k) be center of circle.Circle touches the y-axis.
∴ Radius of circle =h
Equation of circle-
(x−h)2+(y−k)2=h2.....(1)Since the circle passes through (0,2)
Therefore,
h2+(2−k)2=h2
⇒(k−2)2=0
⇒k=2
Given that the circle also passes through (−1,0),
Therefore,
(−1−h)2+22=h2
h2+1+2h+4=h2
h=−25
Substituting the value of h and k in eqn(1), we get