It's a Question of your Career!

Hello,

First of congratulations for scoring such phenomenal marks. It is difficult to say what rank would be based on the marks because it depends on different factors like how many candidates appeared and how they scored in comparison to you.

You can use this rank predictor to know your

Hey,

Your concern completely depends upon school. School management plans the division of marks. For few schools they must consider even class test on the other hand some just focus on mid and end . So the division of marks vary from school to school. What the school do is

Hii

Your querry seems to be incomplete.  It seems that you have missed the detail of the course and college, category and quota of which you want cutoff. So, please rewrite your querry giving these details-

Entrance exam name, category, course/discipline,  other quota

Hope it helps

Direct Admission Process: Student securing 80%+ agg. in Class XII (CBSE/ISC/State-Boards of 2019/2020) are exempted from selection process. Selection will be only on the basis of Amity Application Form. The Cost of the Admission Form is Rs. 1,100 /-

Due to an unprecedented situation arising out of COVID-19, Amity University

Hi Aspirant,

Based on your rank you will get seat in following colleges.

1.Rajarambapu institute of technology.

2.Marathwada mitra mandals college of engineering.

3.Dr.D.Y.Patil institute of technology.

4.Sanjivani college of engineering.

5.Walchand institute of technology.

for more colleges go through the below link:

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Thank you.

hello aspirant

in terms of overall  , MANIT bhopal is among the top nit of india . it is a vey good institute and better than IET . the  average package offered in this college is 9 lpa while tha highest is 20 lpa but for metallurgy i am not

There will be total 75 questions including 25 each from Physics, Chemistry and Mathematics.

From each subject there are 20 objective question with only 1 correct option and 5 numerical value question.

4 marks will be awarded as a correct answer. 1 mark will be deducted for each wrong answer

The oxidation number of chlorine decreases from +7 to +3 and the oxidation number of O  increases from -1 to 0.SO  CI2O7 is oxidizing agent and H2O2 is reducing agent .

ion electron method

the oxidation half reaction is H2O2--->O2

To balance oxidation number 2 electrons are added

H2O2--->O2+2e-

2

Hello Aspirant,

See it is little bit difficult to suggest exactly that in which college you will get seat or not because different colleges have different cut-offs for State quota and All India Quota. Also, cut-offs are bound to change every year depending upon numerous factors such as the number