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Dear aspirant,
According to your question and taking into consideration that you want to know best college in terms of placements.
I would recommend you to go for andhra pradesh as there are really good engineering colleges as compared to telengana. The companies which comes to these colleges are really
Dear Aspirant,
Yes,if you have registered your gmail id for the procedure,then the otp will get generated and will be send on your gmail id as well as mobile number.
Thank you
Hi Manu Preetha !
Hope you did well in NEET 2020:)
Use the below link to predict your rank based on your expected score:-
NEET rank Predictor
https://medicine.careers360.com/neet-rank-predictor
Use the below link for predicting colleges in state counseling of Tamil Nadu:-
https://medicine.careers360.com/neet-state-college-predictor?utm_source=google-search&utm_medium=paid&utm_campaign=neet-clgpd&gclid=Cj0KCQjwzbv7BRDIARIsAM-A6-1yqqWjtw_B_cs71EZT-nGfoU2SlcTYJoA0rlCK6VZZPNHgyZzahBUaAnYKEALw_wcB
This will help you !
Hey!
NEET Exam question paper is same for all the cadidates consisting of same question but different exam codes are given for the paper with the shuffling of the questions to avoid any cheating incidence during the exam.
All the best
In Maharashtra VJNT caste comes under OBC i.e Other Backward Category.Therefore the rules and regulation and the reservation that OBC gets is also same for VJNT caste even for competetive exam the cutoff and fee structure of the institute is same as OBC for VJNT caste.
According to your question and taking into consideration that you want to know the comparison between nit Trichy eee and dtu ece.
I would undoubtedly recommend you nit trichy eee as apart from that it has tag value ,it also has one of the best placements and is
Hello Aspirant, hope you are doing good.
Firstly, congratulations for scoring such amazing marks in JEE Mains, it really takes a lot of hardwork and dedication. Now coming to your question, according to your marks, i would suggest you to apply for the top NITs like NIT Durgapur, NIT Trichy,
Hello !
f(x)= sin [{n*(n+1)/2}^2x]
we already know that period of f(ax+b) is T/|a|.
so, since period of sin is 2pi, the period of f(x) will be 8pi/[n*(n+1)]^2
Hope this helped!
Hello There ,
With the marks which you have scored , you would have less chances to get core B.Tech streams although you have some chances for chemical , manufacturing and civil in goa and hyderabad (if cutoff decreases due to various factors this year 2020) . You can get
hello,
Calicut university has released 3 formulas to convert the CGPA into percentage. They have divided into 3 categories,
So for the range 40 to 90 it is 40+(CGPA-0.5) * 10
for 90-100% it is 90+(CGPA-0.5) * 20
Hope it
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