It's a Question of your Career!

Hello Aspirant,

Am sorry to say but with this rank you cannot be selected in any of the NITs and IIITs but you might get some state government college or any other private colleges

Or you can apply next year with more preparation otherwise apply to other courses

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

This

hello aspirant,

Tips to crack NEET exam with only one year of preparation.

1. Work hard with consistency. You need to complete a 2 year syllabus in one year. If your basic concepts of class 11 are clear, studied from NCERT, then you have an advantage. Otherwise be prepared for some

Hello Aspirant,

Honestly Its difficult to get a government college by this score.According to analysis of previous year cutoffs its easy for you to get a seat in the following colleges:

GITAM Institute of Medical Sciences & Research, Visakhapatnam

(MBBS - Bachelor of Medicine and Bachelor of Surgery)

Bharati Vidyapeeth

Hi Sanjeet,

I think you forgot to mention the name of college or university you are referring to.

For any general college or university, if you search that college on Careers360 App or website than you will get to know all about the college details like Courses, facilities, reviews, ratings

Each State has its different cut offs for various Categories. But speaking in general, to qualify in NEET a Candidate belonging to OBC Category should score atleast 40 percentile of the top NEET score. That is the cut off formula. In 2019, it was 107-133 which was 15 marks more

hey,

here are the best medical courses other than MBBS

1. bachelor of dental surgery BDS

2. bachelor of ayurvedic medicine and surgery  BAMS

3. bachelor of homeopathic medicine and surgery BHMS

4. bachelor of unani medicine and surgery

5. bachelor of physiotherapy

6. bachelor of veterinary science

7. bachelor

Dear Student,

As per last year's data, the rank that you mentioned is close to last year's closing rank of following branches.

Branch name                                      Closing Rank

Chemical Engg . (in Round 2)           164457

Electrical Engg .  (In Round 3)           148958

Material Science & Engg (In Rd 2)     184287

You can

Hello,

2(x-1)^2+2(y-1)^2=(x+y+2)^2

√ (x-1)^2+(y-1)^2 = |x+y+2/√1+1|

It represents a Parabola having

Focus at (1,1) &

Directrix is x+y+2=0

The equation of the axis is y-1=1(x-1)

i.e y= x

Y^2= 4ax

a=√2

So, y^2=4(√2)x

h=k, since(h,k) is a point on the axis of the parabola

Let the point be (x1,0)

For

Hello Aspirant,

Congratulations for your Good rank.

As you haven't mention the Exam name. It is important to mention the exam name. I think you are talking about JEE MAINS .At this rank you have chances to get seat in JAC Delhi. According to previous year cutoffs, you have chance