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105 Views

BAMS cutoff for government colleges

Ankur Dubey Student Expert 9th Oct, 2020

Hello

Since cutoff varies year by years and depends upon the various factors. The factors are number of student attempted , highest marks , etc.

For General category  cut off is around 420+

And for backward classes it is around 400+ for government colleges

For private colleges cutoff is lower

70 Views

my sml number is 477 so will i get government college in Maharashtra and i am st candidate

Shivam Khare 18th Nov, 2020

Hello Dear Student,

Please Elaborate your Question, are you asking Question for Maharashtra NEET Counselling? If yes then please mention your All India Rank for better Predictions, because According to your State Merit list number it's really hard to predict Colleges for you. But here I am giving you the

47 Views

du me ews ki validity hai kya kuch?.....jaise mera 6 march 2020 ko bna tha.....toh kya voh du me valid hai?

Abhishek Singh Tomar 18th Nov, 2020

According to the information you have to make recent ews certificate nearly one or two months before admission or uploading the certificate  because they always demand recent certificate that will also bein fruitful recent one.

81 Views

As MHT CET Of Maharashtra has decided to take Exams In PCB AND PCM GROUP separately I want to ask : I have Given PCB group exam and now my next exam Is of PCM And i dont want to give pcm , So if i didnt go to pcm exam will my pcb paper also get canceled? please tell me

Ankur Dubey Student Expert 10th Oct, 2020

Hello

Since many student were confused about their future and don't take decision whether they go for engineering or medical  field so they go for both of them.

No your pcb will not get cancelled if you not give pcm paper. Ao you can go for which you are interested

61 Views

which iiits are better than last 10 nits in ECE branch

Nikhitha Sai 10th Oct, 2020

Hello student, Here are the few of Indian Institute of Information Technology's which are better than last 10 National Institute of Technology's in electronics and communication branch.

1. Indian institute of information technology, kancheepuram

2. Indian institute of information technology, Hyderabad

3. Indian institute of information technology, Bhubaneswar

4. Indian

54 Views

which iiits are better than last ten nits

Nikhitha Sai 10th Oct, 2020

Hello student, Here are the few of Indian Institute of Information Technology's which are better than last 10 National Institute of Technology's

1. Indian institute of information technology, kancheepuram

2. Indian institute of information technology, Hyderabad

3. Indian institute of information technology, Bhubaneswar

4. Indian institute of information technology, Allahabad

110 Views

I got 27512 category rank in jeemains 2020.will i get seat in NITs and IIITs,and i belong to obc-ncl category.

Vedansh Avlani 9th Oct, 2020

Dear candidate,

Firstly congratulations on achieving such a good rank in JEE Mains. Since you have not mentioned your home state it might be tough to predict any NIT or IIIT for you. But you can use the college predictor link to check for which colleges you might be eligible

175 Views

sir i got 65% in jee can i get seat in any nit

NILUTPOL Student Expert 9th Oct, 2020
Hello
With such a Percentile in JEE Mains, it would be hard for you to get a seat in any government engineering colleges like NITs IIITs and GFTIs.
If you are from General Category, OBC or EWS category, then you have no chances of getting a seat as you have
75 Views

with 90.37 percentile in jee mains can i expect the NIT. having OBC(ncl) reservation from maharashtra?

NILUTPOL Student Expert 9th Oct, 2020
Hello,
With 90 percentile in JEE Mains, your rank in the JEE Mains common rank list would be more than 80000. Even your OBC category rank would be high. With such a rank, you won't be able to get a seat in the top NITs IIITs and GFTIs.

You might
1000 Views

if the circle X square + y square - 4 x + 6 y + y is equals to zero has radius 4 find a

Nikhitha Sai 10th Oct, 2020

hello student,

Here is the solution.

So, the equation is

X^2+Y^2-4X+7Y =0 ---------------------------------------------------------------------------------------(I)

Radius = 4

We need to find a.

((X-2)^2-4)+((Y+3.5)^2-12.25)=0

(X-2)^2+(Y+3.5)^2 = 16.25 ----------------------------------------------------------------------------(1)

Since radius is given as 4, this 16.25 is rounded to 16

SO the actual equation is X^2+Y^2=R^2

Which is modified to:

(X-a)^2+(Y+b)^2 =

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