It's a Question of your Career!

hello,

below are the details of correction dates of neet ug:

Hi aspirant, since you have 345 marks in your NEET exam so accordingly your rank will lie under 651-750, on behalf of that below are  some of the top colleges in which you can get in;

• King George's Medical University, Lucknow
• Maulana Azad Medical College, New Delhi
• Vardhman Mahavir Medical

Dear Aspirant,

You can download your certificate and take a print out of it and then at attest your own signature on it. Self Attest means you have sign on the print out. After self attesting your certificate then submit it for your concerned admission.

Hope this helps.

Good Luck!

Hello

As your profile suggest you are from Rajasthan and I assume you are general category student as you haven't mentioned category name.

At your marks there are no any chances of getting govt college through AIQ or State quota counselling. Last year rajsthan neet cut off for Gen category

Hello Anitha,

Fees for B.Tech Computer Science Engineering in BVRIT College of Engineering for Women, Hyderabad is Rs. 65,000 per annum.

Admission into B.Tech is based on TS EAMCET Rank or JEE Mains Rank. There are 180 seats in this College for B.Tech Computer Science Engineering branch.

The candidates must

Jeremy Bentham was a philosopher and reformer, born in England.

Utilitarianism is a moral theory which talks about what is right, and what is wrong, and depending upon what is right and wrong, how people and institutions should behave and make decisions.

The is the principle of utility and of

There are numerous scholarships programs for UG students are available from the state government/central government/insitutions itself for meritorious students studying in UG courses. Now depending on your course you have to select the scholarship if you are eligible. Remember for most of the scholarship two criterions are followed. The first

Hello aspirant!!

Tamil Nadu Engineering Admissions counselling is done for filling the Engineering seats in Tamil Nadu based upon the cutoff marks scored in 12th class

The cutoff for TNEA is calculated as follows:

Cutoff = M + (P/2) + (C/2)

Where M refers to the mathematics marks, P denotes

Hi

In 2019 MLRIT campus b.tech IT (information technology) closing rank for oc boy is 23924 and in CMRIT technical campus for b.tech cse( computer science engineering) the closing rank is 20123. These are cutoff closing ranks for eamcet in 2019 please choose accordingly .

Hope this will help you

• Motherhood University, Roorkee
  
• Pestle Wood College of Information Technology, Dehradun
  
• Modern Institute of Technology, Rishikesh
  
• Shakuntala Devi Educational Institute, Dehradun