It's a Question of your Career!

Dear aspirant !!

Hope you are doing great !

The authorities revised the AEEE 2022 exam date on the official website to June 17 to 19 and July 31 to August 2 for phase 1 and 2.
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AEEE 2022 Result Date.You have to wait for sometime

Hello,

You haven't mentioned your category, the cut off is category, course and branch specific. Here is the previous year cut off to get admission to Computer Science Engineering in Anna University Regional Campus - Coimbatore

• General: 190.57
• BC: 188.71
• BCM: 183.02
• MBC: 188.98
• MBCDNC:  185.1
• MBCV: 187.64
• SC: 186.5

Dear aspirant !!

Hope you are doing great ! It depends on the students ,if you understand the concept from old lecture then follow them if not then follow Arjuna jee . However in my opinion the old lecture can't be compare with anything.  They are really - really awesome

Hi there.

It is very essential to get a good cgpa throughout your college years in order to get placed in a good company during campus placements.   But at the very same time a student should know that different companies have different criteria for selecting a candidate. Some companies do

Hello Kushmit,

You have mentioned Vardhaman College, Itarsi in your question, so I'm considering it as giving information based on it.

Vardhaman College, Itarsi does not offer B. Sc Computer Science course. The courses offered by Vardhaman College, Itarsi are listed below.

B. Ed

M. Ed

D. Ed

All these

Dear aspirant !

Hope you are doing great ! I will consider the average paper so to get 85 percentile in average paper of jee mains you need to score around 50 to 60 marks , marks can differ depending on difficulty level of the examination . So prepare now

Dear aspirant !

Hope you are doing great !! It will be released very soon ,wait for sometime also .

KVPY Result 2022 - Indian Institute of Science (IISc), Bangalore will release the result of KVPY 2022 in June 2022 on the official website of KVPY i.e. kvpy.iisc.ernet.in.
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KVPY

Hello!

Your question is incomplete, you have not mentioned the name of any college. Please specify the name of the college you want to enquire about so that I can give you an accurate answer.

If you are asking about Indira Gandhi Balika Niketan College Jhunjunu, then yes, it is

1. y=sqrt(ax+b)

dy/dx = (a)/(2*(root(ax+b))

this is according to the chain rule.

2. y=ln(2x+3)

dy/dx=(2)/(2x+3)

this is also according to the chain rule of differentiation.

3. y=e^(2x+3)

when we apply chain rule of differentiation in this, we get:

dy/dx=(2)*(e^(2x+3))

Hope I have answered your question. All the best!

Dear aspirant

You are medicine aspirant so hope you are enquiring about MBBS course in st John's medical College as you have tagged this college in your question.

Without neet you can't get admission in any medical College to study MBBS whether it's at John's or any other

NEET is