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Question : In a shop, a discount of 8% is provided. If the total payable after the discount is more than INR 5,000 and an additional discount of 20% is provided, then determine the final amount to be paid by the customer, if he buys 12 products each of price INR 750.
Option 1: INR 6,724
Option 2: INR 6,624
Option 3: INR 6,424
Option 4: INR 6,524
Correct Answer: INR 6,624
Solution : First discount($a$) = 8% Second discount($b$) = 20% Effective discount = $a+b-\frac{ab}{100} = 20 + 8 - \frac{20×8}{100} = 28-1.6 = 26.4$% Marked price of 1 product = INR 750 Marked price of 12 products = 12 × 750 = INR 9000 Amount discounted
Question : Directions: Select the option that is related to the third number in the same way as the second number is related to the first number. 8 : 514 :: 6 : ?
Option 1: 228
Option 2: 208
Option 3: 218
Option 4: 238
Correct Answer: 218
Solution : Given: 8 : 514 :: 6 : ?
Add 2 to the cube of the first number to obtain the required number. Like, 8 : 514→83 + 2 = 512 + 2 = 514 Similarly, 6 : ?→63 + 2 = 216 +
Question : Directions: In the following question, select the number that can be placed at the sign of the question mark (?) from the given alternatives.
Option 1: 11
Option 2: 31
Option 3: 32
Option 4: 37
Correct Answer: 31
Solution : Given:
In each column, the fourth number is the sum of the square of the second number and the product of the first and the third numbers.
Column 1: (2 × 7) +
Question : The smallest whole number that is to be multiplied by 59535 to make a perfect square is $x$. The sum of digits of $x$ is:
Option 1: 9
Option 2: 5
Option 3: 7
Option 4: 6
Correct Answer: 6
Solution : Factorization of the 59535 = 5 × 35 × 72 It needs to be multiplied by 5 × 3 = 15 to get a perfect square. $\therefore$ Sum of digits = 1 + 5 = 6 Hence, the correct answer is 6.
Question : Directions: In the following question, find the odd number pair in the given alternatives.
Option 1: 3 – 28
Option 2: 2 – 9
Option 3: 5 – 124
Option 4: 4 – 65
Correct Answer: 5 – 124
Solution : Let's check the options – First option: 3 – 28→(3)3 + 1 = 27 + 1 = 28 Second option: 2 – 9→(2)3 + 1 = 8 + 1 = 9 Third option: 5 – 124→
Question : Bal, Pal and Lal were the most prominent leaders of the
Option 1: Swaraj Party
Option 2: Militant National Party
Option 3: Gadar Party
Option 4: Congress Party
Correct Answer: Congress Party
Solution : The correct answer is Congress Party
Lal, Bal, and Pal: Lal was Lala Lajpat Rai, Bal was Bal Gangadhar Tilak, and Pal was Bipin Chandra Pal. These three leaders are known as a trio who actively promoted Indian goods and popularised the Swadeshi Movement
Question : In the given figure, $\mathrm{DE} \| \mathrm{BC}$. If $\mathrm{AD}=5 \mathrm{~cm}, \mathrm{DB}=10 \mathrm{~cm}$, and $\mathrm{AE}=8 \mathrm{~cm}$, then $\mathrm{AC}$ is:
Option 1: 24 cm
Option 2: 32 cm
Option 3: 8 cm
Option 4: 16 cm
Correct Answer: 24 cm
Solution : In the given figure, DE || BC Given: AD = 5 cm, DB = 10 cm, and AE = 8 cm Triangles ADE and ABC are similar. Therefore, the ratio of their corresponding sides will be equal. ⇒ $\frac{AD}{AB} = \frac{AE}{AC}$ Putting the values,
Question : The highest title in Judo is:
Option 1: Black Belt
Option 2: 10th Dan
Option 3: Yellow Belt
Option 4: 12th Dan
Correct Answer: 10th Dan
Solution : The correct answer is 10th Dan.
Judo was the first martial art to adopt the ranking system utilized in Go and Shogi. These concepts of "Dan" and "Kyu" were later merged to create the current ranking system. The different coloured belts in judo
Question : Who revived the Theosophical Society ?
Option 1: Mother Teresa
Option 2: Annie Besant
Option 3: Florence Nightingale
Option 4: Sarojini Naidu
Correct Answer: Annie Besant
Solution : Correct Answer is Annie Besant
The history of modern Indian religion, society, and culture includes a significant contribution from the Theosophical Society. It supported the strengthening and resurgence of Buddhism, Zoroastrianism, and other antiquity religions .Theosophical Society in Madras was led by Annie Besant,
Question : A rectangular carpet has an area of 120 m2 and a perimeter of 46 m. The length of its diagonal is:
Option 1: 23 m
Option 2: 13 m
Option 3: 17 m
Option 4: 21 m
Correct Answer: 17 m
Solution : Let the length of the rectangle as $l$ and the width as $w$. The area of the rectangle, $lw = 120\ \text{m}^2⇒l=\frac{120}{w}$ The perimeter of the rectangle, $2(l + w) = 46\ \text{m}$ $⇒l + w = 23$ putting the value of $l$, we
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