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Question : What is the value of ‘a’ in the below equation? {(5 × 5 × 5 × 5 × 5 × 5)5 × (5 × 5 × 5 × 5 × 5)8} ÷ (5 × 5) = (625)a
Option 1: 14
Option 2: 17
Option 3: 16
Option 4: 15
Correct Answer: 17
Solution : Given: {(5 × 5 × 5 × 5 × 5 × 5)5 × (5 × 5 × 5 × 5 × 5)8} ÷ (5 × 5) = (625)a ⇒ {(56)5} × (55)8} ÷
Question : A shopkeeper lists the price of an article as Rs. 500. But he gives a certain discount which allows the buyer to pay Rs. 500 for the article including 10% sales tax. The rate of discount is:
Option 1: $10$%
Option 2: $10\frac{1}{11}$%
Option 3: $9\frac{1}{11}$%
Option 4: $12$%
Correct Answer: $9\frac{1}{11}$%
Solution : Given: A shopkeeper lists the price of an article as Rs. 500. The sales tax on the Selling Price is 10%. Let the Selling Price be $x$. So, $\frac{110x}{100}=500$ ⇒ $x=\frac{5000}{11}$ Discount = $500-\frac{5000}{11}=\frac{500}{11}$ So, discount percentage is $\frac{\frac{500}{11}}{500}×100=\frac{100}{11}=9\frac{1}{11}$% Hence, the correct answer is $9\frac{1}{11}$%.
Question : 8 men can complete a task in 45 days. 8 women can complete the same task in 18 days. In how many days will 5 men and 8 women, together, complete the same task?
Option 1: $13 \frac{1}{5}$
Option 2: $12 \frac{4}{5}$
Option 3: $14 \frac{2}{5}$
Option 4: $15 \frac{3}{5}$
Correct Answer: $14 \frac{2}{5}$
Solution : First, use $M_1D_1= M_2D_2$ Where $M_1$ and $M_2$ are men and women and $D1$ and $D_2$ are days. $8M\times 45 = 8 W\times 18$ ⇒ $5M=2W$ So, $5M + 8W=2W + 8W = 10W$ Now, $8\times 18 = 10\times D_3$ ⇒ $D_3 = \frac{8\times
Question : The average of 11 results is 50. If the average of the first six results is 49 and that of the last six is 52, the sixth number is:
Option 1: 48
Option 2: 50
Option 3: 52
Option 4: 56
Correct Answer: 56
Solution : Given: The average of 11 results is 50. The average of the first 6 results is 49. The average of the last 6 results is 52. According to the question, The sum of 11 results = 50 × 11 = 550 The sum of the
Question : The term "Kammakaras" in ancient times is related to ______.
Option 1: landless agricultural labourers
Option 2: craftsmen
Option 3: tax collecting officer
Option 4: goldsmith
Correct Answer: landless agricultural labourers
Solution : The correct option is landless agricultural labourers.
In ancient times, the term "Kammakaras" referred to landless agricultural labourers. These individuals worked in the fields but did not own the land they cultivated. Dependent on landowners, they were often vulnerable to economic and
Question : Directions: Select the correct mirror image of the given figure when the mirror is placed at AB as shown.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear closer to the mirror in the reflection. So, according to the above property and the information provided, the mirror is placed on the right side of the figure (on line AB). So, the left side of the
Question : A man makes four trips of equal distances. His speed on the first trip was 720 km/hr and in each subsequent trip, his speed was half of the previous trip. What is the average speed of the man in these four trips?
Option 1: 104 km/hr
Option 2: 156 km/hr
Option 3: 192 km/hr
Option 4: 288 km/hr
Correct Answer: 192 km/hr
Solution : A man makes four trips of equal distances. His speed on the first trip was 720 km/hr. In each subsequent trip, his speed was half of the previous trip. Let's denote the distance of each trip as d. For the first trip, his speed
Question : Four sentences are given, out of which three have spelling errors. Choose the sentence with all the correctly spelt words.
Option 1: They superseded the old statute with a new one.
Option 2: They will be celebrating their twelth anniversary this April.
Option 3: He had no sense of rhythme whatsoever.
Option 4: I wrote her a reciept for the money.
Correct Answer: They superseded the old statute with a new one.
Solution : The correct choice is the first option.
In the second option: Incorrect - twelth, correct - twelfth
In the third option: Incorrect - rhythme, correct - rhythm
In the fourth option: Incorrect - reciept, correct - receipt
Question : If $\sqrt3=1.732$, then the value of $\frac{9+2\sqrt3}{\sqrt3}$ is:
Option 1: 7.169
Option 2: 7.196
Option 3: 5.198
Option 4: 7.296
Correct Answer: 7.196
Solution : Given: $\sqrt{3} = 1.732$ $\frac{9+2\sqrt{3}}{\sqrt{3}}$ To eliminate the root from the denominator, multiply and divide by $\sqrt{3}$ = $\frac{9+2\sqrt{3}}{\sqrt{3}}$ × $\frac{\sqrt{3}}{\sqrt{3}}$ = ${\sqrt{3}×9+\sqrt{3}×2\sqrt{3}}$ = $\frac{\sqrt{3}×9+6}{3}$ = $\frac{3(3\sqrt{3}+2)}{3}$ = $3\sqrt{3}+2$ = $3×1.732+2$ = $7.196$ Hence the correct answer is 7.196.
Question : Directions: Select the option that is related to the third number in the same way as the second number is related to the first number. 441 : 485 :: 676 : ?
Option 1: 729
Option 2: 740
Option 3: 730
Option 4: 1030
Correct Answer: 730
Solution : Given: 441 : 485 :: 676 : ?
Determine the square of the square root of the first number after adding one in it, and then add 1 to the resultant, to get the second number in each number pair – 441 : 485 →(√441
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