1 Million+
Questions
50k +
Active Users
24hrs max.
Answering Time
Question : Directions: Which of the option figures is the exact mirror image of the given problem figure when the mirror is held on the right side of the problem figure?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection. Here, according to the information provided, the mirror is placed on the right side of the figure. So, the left side of the reflected image will appear as the right
Question : The area of two similar triangles is 324 cm2 and 289 cm2, respectively. What is the ratio of their corresponding altitudes?
Option 1: $\frac{17}{18}$
Option 2: $\frac{17}{19}$
Option 3: $\frac{19}{17}$
Option 4: $\frac{18}{17}$
Correct Answer: $\frac{18}{17}$
Solution : The ratio of their altitudes will be equal to the ratio of the square roots of their area. $\frac{A{_1}}{A{_2}} = \frac{h{_1}^2}{h{_2}^2}$ ⇒ $\frac{324}{289} = \frac{h{_1}^2}{h{_2}^2}$ ⇒ $\frac{h{_1}}{h{_2}}=\sqrt\frac{324}{289}$ ⇒ $\frac{h{_1}}{h{_2}} = \frac{18}{17}$ Hence, the correct answer is $\frac{18}{17}$.
Question : Directions: Select the correct mirror image of the given figure when the mirror is placed on the right side.
Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection. Here, according to the information provided, the mirror is placed on the right side of the figure (on Line AB). So, the left side of the reflected image will appear
Question : Find the value of the given expression. $\frac{4}{3} \tan^2 45^{\circ}+3 \cos^2 30^{\circ}-2 \sec^2 30^{\circ}-\frac{3}{4} \cot^2 60^{\circ}$
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{\sqrt{2}}{3}$
Option 4: $\frac{3}{\sqrt{2}}$
Correct Answer: $\frac{2}{3}$
Solution : Given: $\frac{4}{3} \tan^2 45^{\circ}+3 \cos^2 30^{\circ}-2 \sec^2 30^{\circ}-\frac{3}{4} \cot^2 60^{\circ}$ $=\frac{4}{3} \times 1 +3 ( \frac{\sqrt3}{2})^2-2 (\frac{2}{\sqrt3})^2-\frac{3}{4} (\frac{1}{\sqrt3})^2$ $= \frac{4}{3} \times 1^2 +\frac{9}4-\frac{8}3-\frac{3}{4}\times \frac{1}3$ $= \frac{4}3+\frac{9}4-\frac{8}3-\frac{1}4$ $= \frac{16+27-32-3}{12}$ $= \frac{2}3$ Hence, the correct answer is $\frac{2}3$.
Question : On a partnership basis, A and B invested in a ratio of 5 : 6. At the end of 8 months A withdrew his capital. If they shared the eventual profit in the ratio of 5 : 9, then what is the number of months for which B invested his capital?
Option 1: 6 months
Option 2: 10 months
Option 3: 12 months
Option 4: 11 months
Correct Answer: 12 months
Solution : A's initial investment is 5$x$ and B's initial investment is $6x$, where $x$ is a positive constant. after 8 months, A's effective investment for the entire duration is $5x × 8$ B's effective investment is $6x × t$, where $t$ is the number of
Question : On a sum of money for 2 years compound interest and simple interest are INR 550 and INR 500. Find the rate of interest (per annum).
Option 1: 40%
Option 2: 10%
Option 3: 20%
Option 4: 30%
Correct Answer: 20%
Solution : Given: On a sum of money for 2 years compound interest and simple interest are INR 550 and INR 500. From the given information we can conclude that, The interest of INR $\frac{500}{2}$ i.e., INR 250 in 1 year is INR (550 – 500) =
Question : Select the most appropriate option that can substitute the underlined word in the given sentence. None of the countries involved in war were ready to broach the issue of retreat.
Option 1: turn down thoughtlessly
Option 2: bring up for discussion
Option 3: underestimate the worth of
Option 4: disregard contemptuously
Correct Answer: bring up for discussion
Solution : The second option is correct.
The most suitable option to substitute the underlined word broach in the given sentence is bring up for discussion. This is because broach means to introduce or raise a topic for discussion, and among the provided options,
Question : Directions: Pointing towards a girl, Rajan said, "She is the daughter of my mother's daughter". Then how is the girl related to Rajan?
Option 1: Daughter
Option 2: Niece
Option 3: Nephew
Option 4: Uncle
Correct Answer: Niece
Solution : As per the given information, the family tree will be as follows –
Here, the quadrilateral represents the male, and the circular figure represents the female in the figure.
So, from the above family tree, the girl is Rajan's niece. Hence, the second option is
Question : The Indira Sagar Dam is built over River Narmada in which of the following states of India?
Option 1: Karnataka
Option 2: Gujarat
Option 3: Madhya Pradesh
Option 4: Kerala
Correct Answer: Madhya Pradesh
Solution : The correct answer is Madhya Pradesh.
The Indira Sagar Dam is located in the state of Madhya Pradesh, India. It is built on the Narmada River, one of the major rivers in central India. The dam serves various purposes, including irrigation, hydroelectric power
Question : If $\tan\theta =\frac{3}{4}$, then the value of $\frac{4\sin^{2}\theta–2\cos^{2}\theta}{4\sin^{2}\theta+3\cos^{2}\theta}$ is equal to:
Option 1: $\frac{1}{21}$
Option 2: $\frac{2}{21}$
Option 3: $\frac{4}{21}$
Option 4: $\frac{8}{21}$
Correct Answer: $\frac{1}{21}$
Solution : $\frac{4\sin^{2}\theta–2\cos^{2}\theta}{4\sin^{2}\theta+3\cos^{2}\theta}$ Dividing this numerator and denominator by $\cos\theta$ we have, $\frac{4\sin^{2}\theta–2\cos^{2}\theta}{4\sin^{2}\theta+3\cos^{2}\theta} = \frac{4\tan^{2}\theta–2}{4\tan^{2}\theta+3}$ Putting the value of $\tan\theta =\frac{3}{4}$ in this expression, we have, = $\frac{4×\frac{9}{16}–2}{4×\frac{9}{16}+3}$ = $\frac{\frac{9}{4}–2}{\frac{9}{4}+3}$ = $\frac{\frac{1}{4}}{\frac{21}{4}}$ = $\frac{1}{21}$ Hence, the correct answer is $\frac{1}{21}$.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update