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Question : No Money bill can be introduced in the Lok Sabha without the prior approval of the 

Option 1: Vice-President 

Option 2: President 

Option 3: Prime Minister 

Option 4: Finance Minister 

Team Careers360 23rd Jan, 2024

Correct Answer: President 


Solution : Correct answer is The President

No Money bill can be introduced in the Lok Sabha without the prior approval of the President.

Money bill in the state assembly can be introduced with the permission of the State Governor. 

Money bill is mentioned in article 110

80 Views

Question : In January 2022, Kriti paid 22% of her monthly salary as EMI. She spent the remaining salary on shopping for groceries and clothes, in a ratio 7 : 5. She spent Rs. 18,200 on shopping for clothes. If, in February 2022, her salary increased by 16%, what was her salary (in Rs.) in February?

Option 1: 66,350

Option 2: 68,520

Option 3: 70,250

Option 4: 64,960

Team Careers360 19th Jan, 2024

Correct Answer: 64,960


Solution : Let her monthly salary be $x$.
Kriti's EMI was 22% of her monthly salary.
$\therefore$ Remaining salary = $0.78x$
Spending on groceries and clothes was in the ratio of $7:5$.
Money spent on clothes = $\frac{5}{12} \times 0.78x$
According to the question,
$\frac{5}{12} \times 0.78x

12 Views

Question : Select the correct indirect form of the given sentence.

Lee said to his wife, "I am very happy today."

Option 1: Lee told his wife that he was very happy today.

Option 2: Lee told his wife that he has been very happy that day.

Option 3: Lee told his wife he was very happy today.

Option 4: Lee told his wife that he was very happy that day.

Team Careers360 25th Jan, 2024

Correct Answer: Lee told his wife that he was very happy that day.


Solution : The correct choice is the fourth option.

Narration Conversion:

In transforming direct speech to indirect speech, it is crucial to select the right reporting verb and make necessary adjustments in tense and pronoun references.

28 Views

Question : A mixture contains milk and water in the ratio 5 : 2. If 4 liters of water is added to the mixture, the ratio becomes 5 : 4. What is the quantity of milk in the given mixture?

Option 1: 2 litres 

Option 2: 8 litres 

Option 3: 5 litres 

Option 4: 10 litres 

Team Careers360 23rd Jan, 2024

Correct Answer: 10 litres 


Solution : Let the initial milk be $5k$ and water be $2k$ litres
Amount of water added = 4 litres 
Now, 
$\frac{5k}{2k+4}=\frac{5}{4}$
⇒ $20k=10k+20$
⇒$10K=20$
⇒ $k=2$
⇒ Amount of milk =$5k=5\times 2$= 10 litres 
Hence, the correct answer is 10 litres.

4 Views

Question : Directions: From the given answer figures, select the one in which the question figure is hidden/embedded.

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 22nd Jan, 2024

Correct Answer:


Solution : Because there is no restriction on the rotation of the figure, we will check all the possible orientations of the question figure in which of the given option figures it can fit itself. By comparison of all option figures, the question figure is embedded only in

4 Views

Question :  Directions: In the following question, select the related word from the given alternatives.
Frame : Picture :: ? : ?

Option 1: Box : Lid

Option 2: Chair : Cushion

Option 3: Cover : Book

Option 4: Window : Screen 

Team Careers360 22nd Jan, 2024

Correct Answer: Cover : Book


Solution : Given:
Frame : Picture :: ? : ? (Here, the first term is used to protect the second term.)

Let's check each option –
First option: Box : Lid; Box is not used to protect lid.
Second option: Chair : Cushion; Cushion is

27 Views

Question : If $\cos^{2}\alpha-\sin^{2}\alpha=\tan^{2}\beta$, then the value of $\cos^{2}\beta-\sin^{2}\beta$ is:

Option 1: $\cot^{2}\alpha$

Option 2: $\cot^{2}\beta$

Option 3: $\tan^{2}\alpha$

Option 4: $\tan^{2}\beta$

Team Careers360 21st Jan, 2024

Correct Answer: $\tan^{2}\alpha$


Solution : Given: $\cos^{2}\alpha–\sin^{2}\alpha=\tan^{2}\beta$
We know that: $1+\tan^{2}\alpha=\sec^{2}\alpha$
So, $\cos^{2}\alpha-\sin^{2}\alpha=\sec^{2}\beta-1$
⇒ $\cos^{2}\alpha-\sin^{2}\alpha+1=\sec^{2}\beta$
⇒ $\cos^{2}\beta=\frac{1}{\cos^{2}\alpha–\sin^{2}\alpha+(\sin^{2}\alpha+\cos^{2}\alpha)}$
⇒ $\cos^{2}\beta=\frac{1}{2\cos^{2}\alpha}$
Also, $\sin^{2}\beta=1-\cos^{2}\beta=1-\frac{1}{2\cos^{2}\alpha}$
So, $\cos^{2}\beta-\sin^{2}\beta$
$=\frac{1}{2\cos^{2}\alpha}-(1-\frac{1}{2\cos^{2}\alpha})$
$= \frac{1}{\cos^{2}\alpha}-1$
$= \sec^{2}\alpha-1$
$= \tan^{2}\alpha$
Hence, the correct answer is $\tan^{2}\alpha$.

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