It's a Question of your Career!

Correct Answer: To maintain one’s position

Solution : The correct choice is the first option.

The idiom to stand one's ground is a figurative expression that means to maintain one's position, especially in the face of opposition, pressure, or difficulty. It does not necessarily imply physical fighting but rather the

Correct Answer: Son’s wife

Solution : Given:
A @ B means A is the husband of B
A & B means A is the mother of B
A # B means A is the daughter of B

As per the given information family tree will be as follows –

Here,

Correct Answer: crossed the Rubicon

Solution : The correct idiom for the bracketed text is the third option.

Explanation: The idiom "crossed the Rubicon" originates from ancient history, referring to Julius Caesar's decision to cross the Rubicon River, leading to irreversible consequences and a pivotal moment in Roman history. In

Correct Answer: Personel

Solution : The correct choice is the fourth option.

The correct spelling is personnel. The incorrect spelling does not have the letter "n".

Personnel: It describes a group of people who follow orders, usually at a company.

Correct Answer: 12321

Solution : Given:
11 : 121 :: 111 : ?

11² = 121 (121 is the square of 11)
Similarly, 111² = 12321 (12321 is the square of 111)

Hence, the third option is correct.

Correct Answer: $\frac{20}{3}$

Solution : To find: LCM of $\frac{2}{3},\frac{4}{9},\frac{5}{6}$
Apply the formula:
LCM of fractions = $\frac{\text{LCM of numerator}}{\text{HCF of denominator}}$
Now, LCM of 2, 4, and 5 is 20, and HCF of 3, 9, and 6 is 3.
LCM of fractions = $\frac{20}{3}$
Hence, the correct answer is

Correct Answer: Dhyanchand

Solution : The correct option is - Dhyanchand.

Field hockey player Major Dhyan Chand, who represented India, is recognized as the game's all-time best.
Due to his exceptional ball control, he was known as The Wizard or The Magician of hockey.
In 1956, the Indian government presented

Correct Answer: 0

Solution : Given, $\mathrm{K}+\frac{1}{\mathrm{~K}}+2=0$
⇒ $K^{2} + 2K + 1 = 0$
⇒ $(K+1)^{2} = 0$
⇒ $K+1 = 0$
$\therefore$ $K = -1$
Now, we have to find $K^{11}+\frac{1}{K^4}$
Putting the value of $K$, we get
$(-1)^{11} + \frac{1}{(-1)^{4}}$
$= -1 + 1 = 0$
Hence,

Correct Answer: 378

Solution : Given:
583 : 295 :: 486 : ?

Here, the sum of the digits of the first number is equal to the sum of the digits of the second number.
Like, 583 : 295; 5 + 8 + 3 = 16 and 2 + 9

Correct Answer: HP

Solution : Given:
GR : KV :: DL : ?

For each pair, add 4 to the place of each letter of the first term to get the second term –
GR→G + 4 = K; R + 4 = V
So, GR is related to KV.