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Question : Directions: SFBV is related to HUYE in a certain way based on a certain relationship between the given letters in the English alphabetical order. In the same way, JQEF is related to QJVU. Which of the given options is CKSW related to following the same logic?
Option 1: BJRV
Option 2: HDPX
Option 3: XPHD
Option 4: DLTX
Correct Answer: XPHD
Solution : Given: SFBV is related to HUYE, and JQEF is related to QJVU.
Write the opposite letter pairs of each letter of SFBV – S→H; F→U; B→Y; V→E Thus, SFBV is related to HUYE. And JQEF is related to QJVU. J→Q; Q→J; E→V; F→U Thus, JQEF
Question :
Directions: In the following question, select the related word from the given alternatives. Brick : Wall :: Cell : ?
Option 1: DNA
Option 2: Organs
Option 3: Chlorophyll
Option 4: Tissue
Correct Answer: Tissue
Solution :
Given: Brick : Wall :: Cell : ?
Like, Bricks make up the wall. Similarly, specialized cells that are clustered together based on their shape and function make up a tissue.
Hence, the fourth option is correct.
Question : Directions: Select the related letter cluster from the given alternatives. LMNO : NQTW :: GHIJ : ?
Option 1: ILOR
Option 2: ILRO
Option 3: ILMO
Option 4: LRMO
Correct Answer: ILOR
Solution : Given: LMNO : NQTW :: GHIJ : ?
Add consecutive even numbers to the letters of LMNO and GHIJ to obtain the related clusters. L + 2 = N; M + 4 = Q; N + 6 = T; O + 8 = W Similarly,
Question : Which of the following dances evolved from "Ekaharya Lasyanga"?
Option 1: Kuchipudi
Option 2: Kathakali
Option 3: Bharatanatyam
Option 4: Odissi
Correct Answer: Bharatanatyam
Solution : The correct option is Bharatanatyam.
"Ekaharya Lasyanga" is a classical Indian dance form that evolved into what is known today as Bharatanatyam. It originated in the temples of Tamil Nadu and has undergone various transformations over the centuries. The name "Ekaharya Lasyanga" refers to the
Question : If $\cos\left(40^\circ+x\right)=\sin 30^\circ$, then the value of $x$ is:
Option 1: $22^\circ$
Option 2: $20^\circ$
Option 3: $19^\circ$
Option 4: $23^\circ$
Correct Answer: $20^\circ$
Solution : $\cos \left(40^\circ+x\right)=\sin 30^\circ$ ....(1) Now we know that $\sin(90^\circ -x)= \cos x^\circ$ $\therefore$ Equation (1) becomes ⇒ $\cos \left(40^\circ+x\right)=\sin (90^\circ-60^\circ)$ ⇒ $\cos \left(40^\circ+x\right)=\cos 60^\circ$ ⇒ $(40^\circ+x) = 60^\circ$ $\therefore x=20^\circ$ Hence, the correct answer is $20^\circ$.
Question : Directions: Select the letter cluster from the given options that can replace the question mark (?) in the following series. ZC, XF, VI, TL, ?
Option 1: RO
Option 2: RQ
Option 3: LQ
Option 4: KO
Correct Answer: RO
Solution : Given: ZC, XF, VI, TL, ?
Subtract 2 from the positional value of the first letter and add 3 to the positional value of the second letter of the given letter cluster. ZC→Z – 2 = X, C + 3 = F XF→X – 2
Question : What is the digit in the unit's place in the number $\frac{15!}{100}$?
Option 1: 5
Option 2: 7
Option 3: 3
Option 4: 0
Correct Answer: 0
Solution : Number of trailing zeroes in $n$! = [$\frac{n}{5}$] + [$\frac{n}{25}$] + [$\frac{n}{125}$] + ....... where [ ] denotes greatest integer function. So, the number of trailing zeroes in 15! = [$\frac{15}{5}$] + [$\frac{15}{25}$] + [$\frac{15}{125}$] + ....... = 3 + 0 + 0 + .....
Question : Identify the freedom fighter who, as a child, hated going to school and found it suffocating and oppressive.
Option 1: Mahatma Gandhi
Option 2: Jawaharlal Nehru
Option 3: Jyotiba Phule
Option 4: Rabindranath Tagore
Correct Answer: Rabindranath Tagore
Solution : The correct option is Rabindranath Tagore.
Rabindra Nath Tagore was a Bengali poet who hated going to school. He got the Nobel Prize in 1913 for his work on Gitanjali. This makes him the first non-European to receive the award. He wrote a
Question : ph value between 6.5 -7.5 makes soil
Option 1: Basic
Option 2: Neutral
Option 3: Acidic
Option 4: none of these
Correct Answer: none of these
Solution : The correct answer is None of these.
pH value of 7 is neutral soultion, less than 7 is acidic and more than 7 is basic. So pH value from 6.5 to 7.5 ranges from acidic, neutal and a little basic. Ideally soil has
Question : The 3rd and 8th terms of an Arithmetic progression are –14 and 1, respectively. What is the 11th term?
Option 1: 14
Option 2: 16
Option 3: 20
Option 4: 10
Correct Answer: 10
Solution : Given: The 3rd and 8th terms of an Arithmetic progression are –14 and 1. Formula for $n^{th}$ term ⇒ $a +(n-1)d$, where $a$ = 1st term, $d$ = common difference and $n$ = number of terms $3^{rd}$ term ⇒ $a +(3-1)d=–14$ ⇒
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