It's a Question of your Career!

Correct Answer: 0

Solution : Number of trailing zeroes in $n$! = [$\frac{n}{5}$] + [$\frac{n}{25}$] + [$\frac{n}{125}$] + ....... where [ ] denotes greatest integer function.
So, the number of trailing zeroes in 15! = [$\frac{15}{5}$] + [$\frac{15}{25}$] + [$\frac{15}{125}$] + ....... = 3 + 0 + 0 + .....

Correct Answer: Rabindranath Tagore

Solution : The correct option is Rabindranath Tagore.

Rabindra Nath Tagore was a Bengali poet who hated going to school. He got the Nobel Prize in 1913 for his work on Gitanjali. This makes him the first non-European to receive the award. He wrote a

Correct Answer: none of these

Solution : The correct answer is None of these.

pH value of 7 is neutral soultion, less than 7 is acidic and more than 7 is basic. So pH value from 6.5 to 7.5 ranges from acidic, neutal and a little basic. Ideally soil has

Correct Answer: 10

Solution : Given: The 3^rd and 8^th terms of an Arithmetic progression are –14 and 1.
Formula for $n^{th}$ term ⇒ $a +(n-1)d$, where $a$ = 1^st term, $d$ = common difference and $n$ = number of terms
$3^{rd}$ term ⇒ $a +(3-1)d=–14$
⇒

Correct Answer: $95^{\circ}$

Solution :

In the given problem, $\angle \mathrm{AOD}$ and $\angle \mathrm{BOC}$ are angles subtended by the chords $\mathrm{AB}$ and $\mathrm{CD}$ at the centre of the circle. 
The angle subtended by a chord at the centre is twice the angle subtended by it at any point on the

Correct Answer: $\frac{2}{\sqrt{13}}$

Solution : Given, $\tan A=\frac{2}{3}$
Let perpendicular and base be 2 and 3 units.
Now, the hypotenuse $= \sqrt{2^2+3^2} = \sqrt{13}$ units
So, $\sin A = \frac{\text{perpendicular}}{\text{hypotenuse}}=\frac{2}{\sqrt{13}}$
Hence, the correct answer is $\frac{2}{\sqrt{13}}$.

Correct Answer: Only I is correct

Solution : Given:
(I)  N is second to the right of K and second to the left of J. M is exactly opposite to N, and M is not sitting in the corner.

According to the given statements –
I. L and P are

Correct Answer:

Solution : Here the pattern is as follows –
1. In the first row number of triangles increases by one.
2. In the second row number of squares increases by one.
3. In the third row number of circles increases by one.
So, the figure in the third

Correct Answer: 154

Solution : Let's check the options –
First option: 119; 119 ÷ 17 = 7
Second option: 85; 85 ÷ 17 = 5
Third option: 51; 51 ÷ 17 = 3
Fourth option: 154; 154 is not divisible by 17

So, only the fourth option is different

Correct Answer: (1)

Solution : The first option is the correct choice.

Explanation: The phrase "needs of the hour" should be replaced with "need of the hour", which is the right form of the idiom, meaning the most important thing at a particular interval, thereby indicating that there was