It's a Question of your Career!

Correct Answer: 6, 2, 4, 5, 7, 3, 1

Solution : Given:
1. Fustian 2. Funerary 3. Fusion 4. Funicular 5. Fuscous 6. Fundament 7. Fuselage

Step 1: We have Fu common in all the given words, so we will start from the third letter. The third letter is n

Correct Answer: Pragmatic

Solution : The third option is the correct choice.

The passage follows a pragmatic structure as it outlines a practical approach or strategy for achieving a specific goal. In this case, the goal is to understand organisational and personal excellence.

The pragmatic approach involves studying individuals who

Correct Answer: 31 March 2026

Solution : The correct answer is 31 March 2026.

The Samagra Shiksha Abhiyan scheme was launched in 2018, and now it has been extended from April 2021 to March 31, 2026. it is an integrated scheme for school education covering the entire range from preschool

Correct Answer: puzzled

Solution : The correct answer is the fourth option.

Explanation: If someone is puzzled, they are confused or unable to understand something clearly. It aligns with the idea of hesitating and studying someone's face with an expression of uncertainty or confusion.

So, the correct sentence would

Correct Answer:

Solution : On comparing the question figure and all the option figures, the following figure will combine and make the complete pattern –

Hence, the second option is correct.

Correct Answer: aquifer

Solution : The correct answer is an aquifer.

In some places, the groundwater is stored between layers of hard rock below the water table. This geological formation is known as an "aquifer." Aquifers act as natural reservoirs, holding and supplying water to wells and springs. They

Correct Answer: Articles 20 and 21

Solution : The correct answer is Articles 20 and 21.

During a national emergency in India, Article 20 and Article 21 maintain their inviolable status.

• Article 20 ensures that individuals cannot be subjected to retrospective or ex post facto laws, meaning a person cannot

Correct Answer: $-\frac{3}{5}$

Solution : Given: $\tan\alpha=2$
We know that $\sec^{2}\alpha = 1 + \tan^{2}\alpha$ and $\operatorname{cosec}^{2}\alpha = 1 + \cot^{2}\alpha$
Since $\tan\alpha = 2$, we have $\sec^{2}\alpha = 1 + (2)^{2} = 5$
Also, $\cot\alpha = \frac{1}{\tan\alpha} = \frac{1}{2}$
So $\operatorname{cosec}^{2}\alpha = 1 + (\frac{1}{2})^{2} = \frac{5}{4}$
Putting the

Correct Answer: $\frac{13}{15}$

Solution : $\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \div \frac{6}{25}\right)–\left(\frac{2}{7} \times \frac{6}{5} \div \frac{18}{42}\right)\right\}+\frac{19}{30}\right]$
$=\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \times \frac{25}{6}\right)–\left(\frac{2}{7} \times \frac{6}{5} \times \frac{42}{18}\right)\right\}+\frac{19}{30}\right]$
$=[\frac{1}{5}+(\frac{1}{6}\times 5–\frac{4}{5})+\frac{19}{30}]$
$=[\frac{1}{5}+(\frac{5}{6}–\frac{4}{5})+\frac{19}{30}]$
$=[\frac{1}{5}+\frac{1}{30}+\frac{19}{30}]$
$=\frac{26}{30}$
$=\frac{13}{15}$
Hence, the correct answer is $\frac{13}{15}$.

Correct Answer: 34.56%

Solution : Let the radius of the original circle = $r$
So, the Area of the original circle = $\pi r^2$
 Radius of circle after 16% increase = $r+\frac{16r}{100} =1.16r$
Area of new circle = $\pi \times 1.16^2 = 1.3456r^2$
Percentage increase in area 
$\frac{1.3456\pi r^2- \pi