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Question : Directions: Select the option that is related to the fifth number in the same way as the second number is related to the first number and the fourth number is related to the third number. 16 : 49 :: 18 : 55 :: 36 : ?
Option 1: 119
Option 2: 109
Option 3: 107
Option 4: 113
Correct Answer: 109
Solution : Given: 16 : 49 :: 18 : 55 :: 36 : ?
Like, 16 : 49→(16 × 3) + 1 = 48 + 1 = 49 18 : 55→(18 × 3) + 1 = 54 + 1 = 55 Similarly, for 36 : ?→(36 ×
Question : For the annexation of which Indian Kingdom, the "Doctrine of lapse" was not followed?
Option 1: Satara
Option 2: Nagpur
Option 3: Jhansi
Option 4: Punjab
Correct Answer: Punjab
Solution : The correct answer is Punjab.
In 1848, Dalhousie unveiled a plan dubbed the "Doctrine of Lapse". If a king did not have a natural successor, the British would take control of the kingdom under this policy. It prohibits the adoption of sons. The Doctrine
Question : Directions: A square sheet of paper is folded and punched as shown below. How will it look when opened.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the given punched paper is unfolded, it will look like –
Hence, the fourth option is correct.
Question : The value of $\frac{p^{2}- (q - r)^{2}}{(p + r)^{2} - (q)^{2}}$ + $\frac{q^{2} - (p - r)^{2}}{(p + q)^{2} - (r)^{2}}$ + $\frac{r^{2}- (p - q)^{2}}{(q + r)^{2} - (p)^{2}}$ is:
Option 1: 1
Option 2: 2
Option 3: 0
Option 4: 3
Correct Answer: 1
Solution : $\frac{p^{2} - (q - r)^{2}}{(p + r)^{2} - (q)^{2}}$ + $\frac{q^{2} - (p - r)^{2}}{(p + q)^{2} - (r)^{2}}$ + $\frac{r^{2} - (p – q)^{2}}{(q + r)^{2} - (p)^{2}}$ = $\frac{(p + q - r)(p - q + r)}{(p + q + r)(p - q
Question : Select the most appropriate synonym of the given word.
Artful
Option 1: Prudent
Option 2: Benign
Option 3: Ignorant
Option 4: Crafty
Correct Answer: Crafty
Solution : The correct choice will be the fourth option.
Artful: It means clever, skilful, or adept cunningly or deceptively; characterized by cunning or trickery.
Crafty: It means clever deceptively or slyly.
In this context, crafty aligns closely with the meaning of artful as both convey a
Question : Directions: In a certain code language, LIFE is coded as 9351, and NEAR is coded as 4692. What is the code for E in the given code language?
Option 1: 3
Option 2: 4
Option 3: 1
Option 4: 9
Correct Answer: 9
Solution : Given: LIFE is coded as 9351, and NEAR is coded as 4692.
Compare both the words and find out the common alphabet and number to obtain the required code. On comparing both words and codes the letter E is common and the number 9 is
Question : Directions: Select the figure that will replace the question mark (?) in the following figure series.
Solution : According to the given figure series, in every alternate box, the geometrical figures/ numbers/ letters shift their position following the below pattern – 1. From Box 1 to Box 2 – Top centre ⇔ Bottom centre; Bottom left ⇔ Bottom right; Top left→Centre of the box→Top
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will make the series logically complete. A_CCD_BCCDA_CCDABC_D
Option 1: CACB
Option 2: DACB
Option 3: BABC
Option 4: BBBB
Correct Answer: BABC
Solution : Given: A_CCD_BCCDA_CCDABC_D
To fill the series we have to divide the series – A_CCD /_BCCD / A_CCD / ABC_D Let's check each option – First option: CACB; ACCCD / ABCCD / ACCCD / ABCBD (No repeated pattern has
Question : Who among the following received the Nobel Prize in Chemistry in 1936 for 'studying the molecular structure through the investigation of dipole moments and the diffraction of X-rays and electrons in gases'?
Option 1: Arnold Sommerfeld
Option 2: Peter Debye
Option 3: Paul Scherrer
Option 4: Erich Huckel
Correct Answer: Peter Debye
Solution : The correct answer is Peter Debye.
Peter Debye received the Nobel Prize in Chemistry in 1936 for "studying the molecular structure through the investigation of dipole moments and the diffraction of X-rays and electrons in gases." The magnitude of the dipole moment is given
Question : There is a 40% increase in the amount in 10 years at simple interest. What will be the compound interest on Rs. 30,000 after 3 years at the same rate?
Option 1: Rs. 3,745.92
Option 2: Rs. 7,491.84
Option 3: Rs. 9,364.80
Option 4: Rs. 5,618.88
Correct Answer: Rs. 3,745.92
Solution : Given: Simple interest on amount $P$ after 10 years = 40% of $P$ Term for Simple Interest, $n_1$ = 10 years Sum for compound interest, $P$ = Rs. 30,000 Term for compound interest, $n_2$ = 3 years Simple interest after $n_1 $ years =
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