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Question : The salary of Amit is 75% of the salary of Aman. The salary of Amit increases by 40% and the salary of Aman increases by 10%. By what approximate percentage is the new salary of Aman more than the new salary of Amit?
Option 1: 6.2%
Option 2: 9.6%
Option 3: 5.5%
Option 4: 4.8%
Correct Answer: 4.8%
Solution : Given: The salary of Amit is 75% of the salary of Aman. The salary of Amit increases by 40% and the salary of Aman increases by 10%. Let Aman's original salary as 100 So, Amit's original salary = 100 × $\frac{75}{100}$ = 75 After the
Question : If $x=\operatorname{cosec \theta}-\sin\theta$ and $y=\sec\theta-\cos\theta$, then the relation between $x$ and $y$ is:
Option 1: $x^{2}+y^{2}+3=1$
Option 2: $x^{2}y^{2}\left ( x^{2}+y^{2}+3 \right )=1$
Option 3: $x^{2}\left ( x^{2}+y^{2}-5 \right )=1$
Option 4: $y^{2}\left ( x^{2}+y^{2}-5 \right )=1$
Correct Answer: $x^{2}y^{2}\left ( x^{2}+y^{2}+3 \right )=1$
Solution : $x=\operatorname{cosec \theta}-\sin\theta$ ⇒ $x=\frac{1}{\sin\theta}-\sin\theta=\frac{1-\sin^2\theta} {\sin\theta}=\frac{\cos^2\theta}{\sin\theta}$ Also, $x^2=(\frac{\cos^2\theta}{\sin\theta})^2$_____ (i) $y=\sec\theta-\cos\theta$ ⇒ $y=\frac{1}{\cos\theta}-\cos\theta=\frac{1-\cos^2\theta}{\cos\theta}=\frac{\sin^2\theta}{\cos\theta}$ ⇒ $y^2=(\frac{\sin^2\theta}{\cos\theta})^2$_____ (ii) So, $x^2+y^2=(\frac{\cos^2\theta}{\sin\theta})^2+(\frac{\sin^2\theta}{\cos\theta})^2$ ⇒ $x^2+y^2=\frac{\cos^4\theta}{\sin^2\theta}+\frac{\sin^4\theta}{\cos^2\theta}$ ⇒ $x^2+y^2=\frac{\cos^6\theta+\sin^6\theta}{\sin^2\theta\cos^2\theta}$ Add 3 to both sides, we get, ⇒ $x^2+y^2+3=\frac{\cos^6\theta+\sin^6\theta}{\sin^2\theta\cos^2\theta}+3$ ⇒ $x^2+y^2+3=\frac{\cos^6\theta+\sin^6\theta+3\sin^2\theta\cos^2\theta(\sin^2\theta+\cos^2\theta)}{\sin^2\theta\cos^2\theta}$ ⇒ $x^2+y^2+3=\frac{(\cos^2\theta+\sin^2\theta)^3}{\sin^2\theta\cos^2\theta}$ ⇒ $x^2+y^2+3=\frac{1}{\sin^2\theta\cos^2\theta}$ ⇒ $x^2+y^2+3=\frac{\sin^2\theta\cos^2\theta}{\sin^4\theta\cos^4\theta}$ ⇒ $x^2+y^2+3=\frac{1}{(\frac{\cos^2\theta}{\sin\theta})^2×(\frac{\sin^2\theta}{\cos\theta})^2}$ From equation
Question : Disguised unemployment in India is mainly related to:
Option 1: agricultural sector
Option 2: rural area
Option 3: factory sector
Option 4: urban area
Correct Answer: agricultural sector
Solution : The correct answer is the agricultural sector.
Agriculture is the primary source of disguised unemployment in India. Agriculture employs the most people in India, accounting for more than half of the total. However, agricultural production is low, and there is an excess of
Question : If $(a+b+c)=14$ and $\left(a^3+b^3+c^3-3 a b c\right)=98$, find the value of $(ab+bc+ca)$.
Option 1: 60
Option 2: 64
Option 3: 65
Option 4: 63
Correct Answer: 63
Solution : Given that: $a + b + c = 14$ and $a^3 + b^3 + c^3 - 3abc = 98$ We have to find the value of $ab +bc +ca$ We know that, $a^3 + b^3+ c^3 - 3abc = 98$ ⇒ $(a^2+ b^2+ c^2 -
Question : Directions: Each of the letters in the word WORKING is arranged in alphabetical order. How many letters are there in the English alphabetical series between the letter which is third from the left and the one which is fourth from the right in the new letter cluster thus formed?
Option 1: One
Option 2: Six
Option 3: Two
Option 4: Four
Correct Answer: Two
Solution : Given: WORKING
Arrange the letters of WORKING in the alphabetical order – W O R K I N G→G I K N O R W
Now, according to the new letter cluster formed, the third letter from the left is K and the fourth letter
Question : Chlorine gas is a major component of which of the following?
Option 1: Water
Option 2: Tear gas
Option 3: Liquefied petroleum gas
Option 4: Gobar gas
Correct Answer: Tear gas
Solution : The correct option is Tear gas.
Chlorine is a prominent component of tear gas, which is normally composed of a variety of chemicals, one of which is chloroacetophenone (CN) or chlorobenzalmalononitrile (CS), both of which decompose and create chlorine gas. Tear gas can
Question : Directions: Select the figure that will replace the question mark (?) in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the given figure series – 1. The triangle inside the pentagon moves from top left to top right, then again from top right to top left, and so on. 2. The rectangle inside the pentagon moves from bottom right to bottom left, then again
Question : Directions: Three statements are given, followed by three conclusions numbered I, II and III. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follow(s) from the statements. Statements: Some cats are dogs. Some dogs are rats. All rats are tigers. Conclusions: I. Some tigers are cats. II. Some tigers are dogs. III. Some rats are dogs.
Option 1: Only conclusions II and III follow
Option 2: Only conclusions I follows
Option 3: Only conclusions I and II follow
Option 4: Only conclusions I and III follow
Correct Answer: Only conclusions II and III follow
Solution : The possible Venn diagram according to the given statements is as follows –
Let's analyse the conclusions – Conclusion (I): Some tigers are cats – From the Venn diagram, there is no definite relation between tigers and cats. Therefore, this
Question : Directions: If A means +, B means ×, C means ÷, and D means –, then the value of the given equation will be 9 A 2 B 6 D 4 C 2 = ?
Option 1: 16
Option 2: 19
Option 3: 27
Option 4: 30
Correct Answer: 19
Solution : Given: 9 A 2 B 6 D 4 C 2 = ?
After replacing the letters with mathematical signs, the equation becomes – = 9 + 2 × 6 – 4 ÷ 2 = 9 + 2 × 6 – 2 = 9 + 12
Question : A man covers half part of a certain distance at 60 km/hr. He covers 40% of the remaining distance at the speed of 12 km/hr and covers the rest of the distance at the speed of 18 km/hr. What is his average speed for the entire journey?
Option 1: 24 km/hr
Option 2: $\frac{58}{3}$ km/hr
Option 3: 36 km/hr
Option 4: 40 km/hr
Correct Answer: 24 km/hr
Solution : Let the total distance be 100 km. Half distance = $\frac{100}{2}$ = 50 km Speed = 60 km/hr Time taken to cover half the distance = $\frac{50}{60}$ = $\frac{5}{6}$ Remaining distance = 50 km Distance = 40% of the remaining distance = $\frac{40}{100}×50$ =
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