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Question : Select the most appropriate antonym of the given word.
Speculate

Option 1: deliberate

Option 2: consider

Option 3: dismiss

Option 4: contemplate

Team Careers360 25th Jan, 2024

Correct Answer: dismiss


Solution : The correct choice is the third option.

Speculate means to engage in contemplation or reflection, often involving assumptions or conjectures. Its antonym, dismiss, means to reject or disregard, to refuse to consider seriously.

The meanings of the other options are as follows:

  • Deliberate:
184 Views

Question : Haripriya Namboodiri is an exponent of which Indian classical dance form?

Option 1: Kathakali

Option 2: Kuchipudi

Option 3: Odissi

Option 4: Bharatanatyam

Team Careers360 19th Jan, 2024

Correct Answer: Kathakali


Solution : The correct answer is Kathakali.

Haripriya Namboodiri is an exponent of Kathakali. It is one of the 8 Indian classical dance forms and one of the 2 native classical dance forms of Kerala. Mohiniyattam and Kathakali are the 2 classical dance forms that originated in

25 Views

Question : The expression $\frac{(1-\sin \theta+\cos \theta)^2(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\sec \theta-\tan \theta)(\tan \theta+\cot \theta)}, 0^{\circ}<\theta<90^{\circ}$, is equal to:

Option 1: $\sin \theta$

Option 2: $2 \cos \theta$

Option 3: $\cot \theta$

Option 4: $2 \tan \theta$

Team Careers360 18th Jan, 2024

Correct Answer: $2 \tan \theta$


Solution : $\frac{(1-\sin \theta+\cos \theta)^2(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\sec \theta-\tan \theta)(\tan \theta+\cot \theta)}$
$=\frac{(1+\sin^2 \theta+\cos^2 \theta-2\sin\theta-2\sin\theta\cos\theta+2\cos\theta)(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\frac{1}{\cos\theta}-\frac{\sin\theta}{\cos\theta})(\frac{\sin\theta}{\cos\theta}+\frac{\cos\theta}{\sin\theta})}$
$=\frac{(2-2\sin\theta-2\sin\theta\cos\theta+2\cos\theta)(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\frac{1-\sin\theta}{\cos\theta})(\frac{\sin^2\theta+\cos^2\theta}{\sin\theta\cos\theta})}$
$=\frac{(2(1-\sin\theta)+ 2\cos\theta(1-\sin\theta)(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\frac{1-\sin\theta}{\cos\theta})(\frac{1}{\sin\theta\cos\theta})}$
$=\frac{((1-\sin\theta)2 (1+\cos\theta)(1-\cos \theta) \sec ^3 \theta\;

48 Views

Question : Select the most appropriate meaning of the given idiom.
Once in a blue moon

Option 1: Occasionally

Option 2: Continuously

Option 3: Rarely

Option 4: Often

Team Careers360 19th Jan, 2024

Correct Answer: Rarely


Solution : The correct choice will be the third option.

Once in a blue moon is an idiomatic expression that indicates something happens very infrequently or seldom.

So, when someone says an event happens once in a blue moon they mean it happens only on rare occasions

12 Views

Question : Directions: Select the option figure in which the given figure is embedded. (Rotation is NOT allowed)

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 19th Jan, 2024

Correct Answer:


Solution : Since the rotation is restricted. So, the embedded figure will have the same orientation as the main figure. By comparison of all the option figures, the given question figure is embedded only in the first option figure.

Hence, the first option is correct.

127 Views

Question : Directions: In a certain code language, BOLT is coded as 2965, DOLE is coded as 5723, TADY is coded as 0368, and MASB is coded as 4819. What is the code for BTO in that code language?

Option 1: 962

Option 2: 865

Option 3: 482

Option 4: 958

Team Careers360 22nd Jan, 2024

Correct Answer: 962


Solution : Given:
1. BOLT ⇒ 2965
2. DOLE ⇒ 5723
3. TADY ⇒ 0368
4. MASB ⇒ 4819

By comparing all the above-coded letters, we find that –
In words 1 and 2, L/O is the common letter and 2/5 is the common code.

13 Views

Question : The layer of the atmosphere in which Radio Waves are reflacted back is called :

Option 1: ionosphere

Option 2: troposphere

Option 3: stratosphere

Option 4: exosphere

Team Careers360 21st Jan, 2024

Correct Answer: ionosphere


Solution : The correct answer is ionosphere.

Ionosphere is responsible for reflection of radio waves back to earth. This layer makes the communication and navigation possible on earth. It extends fro 60 km to 800 km from the earth's crust. It also acts as the boundary between

16 Views

Question : Directions: In the given question, a sentence is given with a blank to be filled in with an appropriate word. Four alternatives are suggested for each question. Choose the correct alternative out of the four alternatives.

It is raining _____. Do not go out.

Option 1: fast

Option 2: soundly

Option 3: strongly

Option 4: heavily

Team Careers360 21st Jan, 2024

Correct Answer: heavily


Solution : The correct choice is the fourth option.

The adverb heavily is the correct choice in this sentence because it describes the intensity of the rain. When you say "It is raining heavily," it means that the rain is falling with great intensity, which might make

49 Views

Question : Select the most appropriate option to substitute the underlined segment in the following sentence.
The newly admitted students has been given a pair of uniforms by the management.

Option 1: are been given a pair

Option 2: has given a pair

Option 3: have been given a pair

Option 4: have being given a pair

Team Careers360 19th Jan, 2024

Correct Answer: have been given a pair


Solution : The correct option is the third option.

Explanation: The subject in the sentence is "newly admitted students" which is a plural noun phrase. The verb "has been" in the original sentence is singular and does not agree with the plural subject.

17 Views

Question : What is the value of $\frac{7}{8}+\frac{8}{11}$ of $[\frac{33}{16}-\frac{5}{12}+(\frac{6}{11}-\frac{5}{12}+\frac{7}{22})] ?$

Option 1: $\frac{6871}{3605}$

Option 2: $\frac{6805}{2987}$

Option 3: $\frac{6907}{3971}$

Option 4: $\frac{6961}{2904}$

Team Careers360 21st Jan, 2024

Correct Answer: $\frac{6961}{2904}$


Solution : $\frac{7}{8}+\frac{8}{11}$ of $[\frac{33}{16}-\frac{5}{12}+(\frac{6}{11}-\frac{5}{12}+\frac{7}{22})]$
$=\frac{7}{8}+\frac{8}{11}\times[\frac{33}{16}-\frac{5}{12}+\frac{59}{132}] $
$=\frac{7}{8}+\frac{8}{11} \times\frac{1105}{528} $
$=\frac{7}{8}+\frac{1105}{726} $
$= \frac{6961}{2904} $
Hence, the correct answer is $\frac{6961}{2904}$.

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