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Question : A boat goes 20 km upstream and 44 km downstream in 8 hours. In 5 hours, it goes 15 km upstream and 22 km downstream. Determine the speed of the boat in still water.

Option 1: 6 km/h

Option 2: 10 km/h

Option 3: 8 km/h

Option 4: 7 km/h

Team Careers360 24th Jan, 2024

Correct Answer: 8 km/h


Solution : Let the speed of the boat in still water be $x$ km/h and 
The speed of stream = $y$ km/h
Speed of boat at downstream = $(x+y)$ km/h
Speed of boat at upstream = $(x−y)$ km/h
Time taken to cover 20 km upstream =

5 Views

Question : Directions: In the following question, select the related word from the given alternatives.
Heart : Cardiologist : : Brain : ?

Option 1: Ophthalmologist

Option 2: Nephrologist 

Option 3: Neurologist

Option 4: Gynaecologist

Team Careers360 18th Jan, 2024

Correct Answer: Neurologist


Solution : Given:
Heart : Cardiologist : : Brain : ?

Like, a cardiologist is a medical specialist who deals with the issues related to the heart.
Similarly, a doctor who specialises in the issues related to the brain is called a neurologist.

Hence, the third option

16 Views

Question : Direction: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

a _ ca _ ca _ caa _

Option 1: caca

Option 2: cacc

Option 3: caac

Option 4: ccca

Team Careers360 21st Jan, 2024

Correct Answer: cacc


Solution : Given:–
a _ ca _ ca _ caa _

Let's check the given options –

First option: caca
The series becomes accaacaccaaa
There is no pattern in the above series.

Second option: cacc
The series becomes ac

21 Views

Question : The length of a rectangle is increased by 10% and breadth is decreased by 10%. The area of the new rectangle is:

Option 1: neither increased nor decreased.

Option 2: increased by 1%.

Option 3: decreased by 2%.

Option 4: decreased by 1%.

Team Careers360 23rd Jan, 2024

Correct Answer: decreased by 1%.


Solution : Let the length and breadth of the rectangle be $a$ and $b$ respectively.
Initial area = $ab$ sq. units
Length after 10% increase = $a + \frac{10}{100}\times a = 1.1a$
Breadth after 10% decrease = $b - \frac{10}{100}\times b = 0.9b$
$\therefore$ New

21 Views

Question : What will be the compound interest on Rs. 21000 at the rate of 10% per annum for 6 months compounded half-yearly?

Option 1: Rs. 1680

Option 2: Rs. 1050

Option 3: Rs. 1850

Option 4: Rs. 1250

Team Careers360 22nd Jan, 2024

Correct Answer: Rs. 1050


Solution : The formula for the calculation of compound interest for half a year,
$\text{Compound interest}=\text{Principal}×(1+\frac{\text{Rate}}{2×100})^{\text{2×Time}}-\text{Principal}$
$⇒\text{Compound interest}=21000×(1+\frac{\text{10}}{2×100})^{\text{2×0.5}}-21000$
$⇒\text{Compound interest}=21000×(1+\frac{\text{1}}{20})^{\text{1}}-21000$
$⇒\text{Compound interest}=21000×(\frac{\text{21}}{20})-21000$
$⇒\text{Compound interest}=22050-21000$
$\therefore\text{Compound interest}=1050$
Hence, the correct answer is Rs. 1050.

16 Views

Question : Directions: If the given words are arranged as per an English dictionary, then which word will appear last?
1. Disturb 2. Distance 3. Distilled 4. Distribution 5. Distort

Option 1: Disturb

Option 2: Distort

Option 3: Distilled

Option 4: Distribution

Team Careers360 23rd Jan, 2024

Correct Answer: Disturb


Solution : Given:
1. Disturb 2. Distance 3. Distilled 4. Distribution 5. Distort

Step 1: Compare the first, second, third, and fourth letters of each word. Since all the words start with the same letter D and are followed by i, s, and t,

43 Views

Question : The following table shows the percentage of students passing out of four colleges (A, B, C and D) over four years. Study the table and answer the question that follows.

Years College
A
College
B
College
C
College
D
2019 68 78 56 78
2020 72 86 78 82
2021 78 91 82 85
2022 80 87 84 87

In which college is the average percentage of passing students over the given four years the least?

Option 1: College D

Option 2: College C

Option 3: College B

Option 4: College A

Team Careers360 25th Jan, 2024

Correct Answer: College A


Solution : Average percentage of student passing in college A over four years = $\frac{68+72+78+80}{4} = \frac{298}{4}$
Average percentage of student passing in college B over four years = $\frac{78+86+91+87}{4} = \frac{342}{4}$
Average percentage of student passing in college C over four years = $\frac{56+78+82+84}{4} =

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