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13 Views

Question : Directions: The bar graph given below represents the number of boys in a school using three apps for three months.


What is the percentage decrease in the number of boys using Facebook from January to February?

Option 1: 26.66%

Option 2: 20%

Option 3: 21.33%

Option 4: 16.66%

Team Careers360 19th Jan, 2024

Correct Answer: 16.66%


Solution : As per the given graph,
The number of boys using Facebook in January = 600
The number of boys using Facebook in February = 500
The percentage decreases $=\frac{600-500}{500}×100=16.66\%$
Hence, the correct answer is 16.66%.

4 Views

Question : If $\theta$ is an acute angle and $\sin(\theta +18^{\circ} )=\frac{1}{2}$, then the value of $\theta$ in circular measure is:

Option 1: $\frac{\pi}{12}$ radians

Option 2: $\frac{\pi}{15}$ radians

Option 3: $\frac{2\pi}{5}$ radians

Option 4: $\frac{3\pi}{13}$ radians

Team Careers360 18th Jan, 2024

Correct Answer: $\frac{\pi}{15}$ radians


Solution : Given that $\sin(\theta +18^{\circ})=\frac{1}{2}$, we need to find the value of $\theta$ in radians.
We know that $\sin30^{\circ}=\frac{1}{2}$,
$\sin(\theta +18^{\circ})=\sin30^{\circ}$
$⇒\theta +18^{\circ}=30^{\circ}$
$⇒\theta=12^{\circ}$
To convert degrees to radians, we use the formula ⇒ Radians = Degrees × $\frac{\pi}{180^{\circ}}$
So, $\theta=12^{\circ}×\frac{\pi}{180}=\frac{\pi}{15}$ radians
Hence, the correct

13 Views

Question : Who among the following is not a Bharat Ratna recipient?

Option 1: Nelson Mandela

Option 2: Khan Abdul Ghaffar Khan

Option 3: Mother Teresa

Option 4: Baldev Singh

Team Careers360 19th Jan, 2024

Correct Answer: Baldev Singh


Solution : The correct option is Baldev Singh

Baldev Singh is not a Bharat Ratna recipient. The other three, Mother Teresa (1980), Khan Abdul Ghaffar Khan (1987), and Nelson Mandela (1990), all received the prestigious award, each signifying India's recognition for their exceptional contributions to humanity.

16 Views

Question : Who among the following wrote Sanskrit grammer?

Option 1: Kalidasa

Option 2: Charaka

Option 3: Panini

Option 4: Aryabhat

Team Careers360 21st Jan, 2024

Correct Answer: Panini


Solution : The correct answer is Panini.

Panini wrote a book called Ashtadhyai. It is an ancient treatise on Sanskrit grammar. He lived between 4th and 5th century BC during the advent of Mauryan empire. Ashtadhyayi means eight texts which is an Sanskrit grammar book which gives

16 Views

Question : If $a = 64$ and $b = 289$, then the value of $\sqrt{\sqrt{\sqrt{a}+\sqrt{b}}-\sqrt{\sqrt{b}-\sqrt{a}}}$ is:

Option 1: $2^{\frac{1}{2}}$

Option 2: $2$

Option 3: $4$

Option 4: $–1$

Team Careers360 22nd Jan, 2024

Correct Answer: $2^{\frac{1}{2}}$


Solution : Given: $a = 64$ and $b = 289$
The given expression is $\sqrt{\sqrt{\sqrt{a}+\sqrt{b}}-\sqrt{\sqrt{b}-\sqrt{a}}}$.
Substitute the value of $a = 64$ and $b = 289$ in the above equation, we get,
$=\sqrt{\sqrt{\sqrt{64}+\sqrt{289}}-\sqrt{\sqrt{289} - \sqrt{64}}}$
$=\sqrt{\sqrt{8+17}-\sqrt{17-8}}$
$=\sqrt{\sqrt{25}-\sqrt{9}}$
$=\sqrt{5-3}$
$=2^{\frac{1}{2}}$
Hence, the correct answer is $2^{\frac{1}{2}}$.

9 Views

Question : Directions: From the given alternative words, select the word that cannot be formed using the letters of the given word.
HARBINGER

Option 1: BARRING

Option 2: GARNER

Option 3: GARBAGE

Option 4: RANGER

Team Careers360 24th Jan, 2024

Correct Answer: GARBAGE


Solution : Given:
HARBINGER

Now, let's compare all the option words with the word HARBINGER –
First option: BARRING; All the letters of BARRING are present in the word HARBINGER.
Second option: GARNER; All the letters of GARNER are present in the word HARBINGER.
Third option: GARBAGE;

13 Views

Question : The value of $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ is:

Option 1: $\frac{35}{48}$

Option 2: $\frac{59}{48}$

Option 3: $\frac{49}{24}$

Option 4: $\frac{35}{24}$

Team Careers360 18th Jan, 2024

Correct Answer: $\frac{59}{48}$


Solution : Given: $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$
We know that $\tan 30^{\circ} = \frac{1}{\sqrt{3}}$
$\sin 30^{\circ} = \frac{1}{2}$
$\cos 45^{\circ} = \frac{1}{\sqrt{2}}$
$\cos 37^{\circ} = \cos (90^{\circ} - 53^{\circ})

16 Views

Question : Given below are four sentences in jumbled order. Pick the option that gives their correct order.

A. Very soon, he bought a young goat.
B. When all his goats left him, Abdul was very lonely.
C. He simply couldn't do without his pets.
D. He thought, "A young goat will stay with me for long."

Option 1: CADB

Option 2: CDBA

Option 3: BCAD

Option 4: BDAC

Team Careers360 19th Jan, 2024

Correct Answer: BCAD


Solution : The third option is the correct choice.

The sequence begins with Abdul experiencing loneliness after all his goats leave him (B), highlighting his emotional connection to the animals. This loneliness is further emphasised in sentence C, explaining that Abdul couldn't do without his pets. Following

13 Views

Question : Who amongst the following got a Nobel Prize in recognition of his discoveries of how salts and water transported in and out of cells in the human body?

Option 1: Roderick MacKinnon 

Option 2: Kurt Wuethrich

Option 3: John E. Sultan

Option 4: H. Robert Horvitz

Team Careers360 25th Jan, 2024

Correct Answer: Roderick MacKinnon 


Solution : The correct answer is Roderick MacKinnon.

Nobel Prize in Chemistry is awarded by the Royal Swedish Academy of Sciences every year. The 2003 Nobel Prize was conferred to Peter Agre and Roderick MacKinnon. They have demonstrated how ions and water are transported through cell

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