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Question : AB is a chord of a circle having a radius of 1.7 cm. If the distance of this chord AB from the centre of the circle is 0.8 cm, then what is the length (in cm) of the chord AB?

Option 1: 4

Option 2: 1

Option 3: 3

Option 4: 2

Team Careers360 21st Jan, 2024

Correct Answer: 3


Solution :
OB = 1.7 cm
OC = 0.8 cm
In $\triangle$ OCB,
$OB^2 = OC^2 + CB^2$
⇒ $1.7^2 = 0.8^2 + CB^2$
⇒ $2.89 = 0.64 + CB^2$
⇒ $CB^2 = 2.89 – 0.64 = 2.25$
$\therefore$ $CB = 1.5$ cm
AB = 2 ×

14 Views

Question : The area of triangle with vertices A(0, 8), O(0, 0), and B(5, 0) is:

Option 1: 8 sq. units

Option 2: 13 sq. units

Option 3: 20 sq. units

Option 4: 40 sq. units

Team Careers360 25th Jan, 2024

Correct Answer: 20 sq. units


Solution : Let (x1, y1) = (0, 8)
(x2, y2) = (0, 0)
(x3, y3) = (5, 0)
Area of a triangle with vertices (x1, y1), (x2, y2),

9 Views

Question : Simplify the following expression.
12 + 2.5 + (1.5 of 4) – 2.6

Option 1: 17.9

Option 2: 18.9

Option 3: 18.1

Option 4: 17.1

Team Careers360 21st Jan, 2024

Correct Answer: 17.9


Solution : 12 + 2.5 + (1.5 of 4) – 2.6
= 12 + (6) - 0.1
= 18 - 0.1
= 17.9
Hence, the correct answer is 17.9.

32 Views

Question : A sum of Rs. 600 becomes Rs. 840 at simple interest in 4 years. In how many years will the sum of Rs. 1500 amount to Rs. 2100 at the same rate of simple interest?

Option 1: 5 years

Option 2: 4 years

Option 3: 2 years

Option 4: 3 years

Team Careers360 19th Jan, 2024

Correct Answer: 4 years


Solution : Given,
P = Rs. 600, A = Rs. 840, and T = 4 years,
Simple interest, SI = Amount – Principal
we can find the rate of interest (R):
⇒ R = $\frac{SI×100}{P×T}$​
⇒ R = $\frac{840−600​}{600×4}×100$
⇒ R = $\frac{240​}{2400}×100$
⇒ R =

18 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error."

Kalidas is (1) / a Shakespeare (2) / of India. (3) / No error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 19th Jan, 2024

Correct Answer: (2)


Solution : The error lies in the second part of the sentence.

Explanation: The article "a" should be replaced with "the" in the sentence, after the noun, that is, Shakespeare, a well-known personality in English literature. So, the definite article "the" should be used here to

18 Views

Question : If $\left(x+\frac{1}{x}\right)=5 \sqrt{2}$, and $x>1$, what is the value of $\left(x^6-\frac{1}{x^6}\right) ?$

Option 1: $22970 \sqrt{23}$

Option 2: $23030 \sqrt{23}$

Option 3: $23060 \sqrt{23}$

Option 4: $22960 \sqrt{23}$

Team Careers360 17th Jan, 2024

Correct Answer: $23030 \sqrt{23}$


Solution : Given, $\left(x+\frac{1}{x}\right)=5 \sqrt{2}$
Squaring both sides, we get,
$\left(x+\frac{1}{x}\right)^2=(5 \sqrt{2})^2$
⇒ $x^2+\frac{1}{x^2}+2\times x\times \frac{1}{x}=25\times 2$
⇒ $x^2+\frac{1}{x^2}+2=50$
⇒ $x^2+\frac{1}{x^2}=50-2$
⇒ $x^2+\frac{1}{x^2}=48$
Subtracting 2 from both sides, we get,
⇒ $(x-\frac{1}{x})^2=48-2$
⇒ $(x-\frac{1}{x})^2=46$
⇒ $(x-\frac{1}{x})=\sqrt{46}$
Now consider, $\left(x^6-\frac{1}{x^6}\right)$
We know, $a^2-b^2=(a-b)(a+b)$
$=(x^3+\frac{1}{x^3})(x^3-\frac{1}{x^3})$
Also, $a^3+b^3=(a+b)(a^2-ab+b^2)$ and

6 Views

Question : Select the option that can be used as a one-word substitute for the given group of words.

The scientific study of the behaviour, structure, physiology, classification and distribution of animals.

Option 1: Zoology

Option 2: Archaeology

Option 3: Petrology

Option 4: Ecology

Team Careers360 20th Jan, 2024

Correct Answer: Zoology


Solution : The correct choice is the first option.

Explanation:

The given group of words refers to the systematic study of animals, encompassing various aspects such as behaviour, structure, physiology, classification, and distribution. The term that precisely encapsulates this scientific discipline is zoology. It is the

19 Views

Question : What is the value of $\tan 6^{\circ} × \tan 45^{\circ} × \tan 84^{\circ}$?

Option 1: $1$

Option 2: $\tan 6^{\circ} \times \tan 39^{\circ}$

Option 3: $3$

Option 4: $\tan 6^{\circ}+\tan 45^{\circ}+\tan 84^{\circ}$

Team Careers360 24th Jan, 2024

Correct Answer: $1$


Solution : $\tan 6^{\circ} × \tan 45^{\circ} × \tan 84^{\circ}$
= $\tan 6^{\circ} × \tan 45^{\circ} × \tan (90^{\circ}-6^{\circ})$
= $\tan 6^{\circ} × \tan 45^{\circ} × \cot 6^{\circ}$
= $\tan 6^{\circ} × \tan 45^{\circ} × \frac{1}{\tan 6^{\circ}}$
= $\tan 45^{\circ}$
= $1$
Hence, the correct answer is

12 Views

Question : 'Hind Swaraj' or 'Indian Home Rule' is written by which of the following freedom fighters?

Option 1: Dadabhai Naoroji

Option 2: Mahatma Gandhi

Option 3: Bal Gangadhar Tilak

Option 4: Annie Besant

Team Careers360 20th Jan, 2024

Correct Answer: Mahatma Gandhi


Solution : The correct option is Mahatma Gandhi.

"Hind Swaraj" by Mahatma Gandhi, published in 1909, is a seminal work advocating Indian self-rule. It critiques modern civilisation's materialism, emphasising moral, and spiritual values. He promoted nonviolent resistance (Satyagraha) as the path to India's independence from

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