It's a Question of your Career!

1 Million+

Questions

50k +

Active Users

24hrs max.

Answering Time

Showing 20921 - 20930 out of 57969 Questions
209 Views

Question : In a school of 720 students, the ratio of boys to girls is 3 : 5. Find how many new boys may be allowed to the school if 18 new girls are admitted, so that the ratio of boys to girls changes to 2 : 3.

Option 1: 42

Option 2: 44

Option 3: 50

Option 4: 38

Team Careers360 24th Jan, 2024

Correct Answer: 42


Solution : In a school of 720 students, the ratio of boys to girls is 3 : 5.
⇒ Number of boys in the school $= 720 × \frac{3}{3+5} =720 × \frac{3}{8}= 270$
⇒ Number of girls in the school $= 720 × \frac{5}{3+5}=720 × \frac{5}{8}= 450$

25 Views

Question : A and B undertake a piece of work for Rs. 250. A alone can do that work in 5 days and B alone can do that work in 15 days. With the help of C, they finish the work in 3 days. If everyone gets paid in proportion to the work done by them, the amount C will get is:

Option 1: Rs. 50

Option 2: Rs. 100

Option 3: Rs. 150

Option 4: Rs. 200

Team Careers360 19th Jan, 2024

Correct Answer: Rs. 50


Solution : Given:
A and B undertake a piece of work for Rs. 250.
A's 1 day's work = $\frac{1}{5}$
B's 1 day's work = $\frac{1}{15}$
(A + B + C)'s 1 day's work = $\frac{1}{3}$
So, C's 1 day's work = $\frac{1}{3}-(\frac{1}{5}+\frac{1}{15})=\frac{1}{3}-\frac{4}{15}=\frac{1}{15}$
The ratio of

12 Views

Question : The famous Battle of Talikota was fought in:

Option 1: 1565 AD

Option 2: 1575 AD

Option 3: 1585 AD

Option 4: 1570 AD

Team Careers360 19th Jan, 2024

Correct Answer: 1565 AD


Solution : The correct option is 1565 AD.

On January 23, 1565, the forces of the Hindu king of Vijayanagara and the four allied Muslim sultanates of Bijapur, Bidar, Ahmednagar and Golconda fought in the Deccan area of southern India in the Battle of Talikota.

8 Views

Question : Directions: A paper is folded and cut as shown below. How will it appear when unfolded?

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 17th Jan, 2024

Correct Answer:


Solution : When the given folded paper is unfolded, it will look like –

Hence, the fourth option is correct.

14 Views

Question : If $x$ is prime number and $-1 \leq \frac{2x-7}{5} \leq 1$, then the number of values of $x$ is:

Option 1: 4

Option 2: 3

Option 3: 2

Option 4: 5

Team Careers360 16th Jan, 2024

Correct Answer: 3


Solution : Given:
$x$ is prime number and $-1 \leq \frac{2x-7}{5} \leq 1$.
So, $-1 \leq \frac{2x-7}{5}$
$⇒-5 \leq 2x-7$
So, $1 \leq x$
Again, $\frac{2x-7}{5} \leq 1$
$⇒2x-7 \leq 5$
$\therefore x \leq 6$
Therefore, values of $x$ are 2, 3, and 5. [as $x$ is

15 Views

Question : The main function of centriole is:

Option 1: to help plant cells with multiplication

Option 2: to help cell division in animal cells

Option 3: to maintain rigidity in plant cell

Option 4: to maintain mineral composition in bacterial cell

Team Careers360 16th Jan, 2024

Correct Answer: to help cell division in animal cells


Solution : The correct answer is to help cell division in animal cells.

Animal cells' cytoplasm contains paired, barrel-shaped organelles called centrioles that are situated close to the nuclear envelope. The skeletal system of the cell is made up of microtubules,

32 Views

Question : Under which scheme did Lieutenant Governor Manoj Sinha inaugurate "UMEED Market Place" in Jammu and Kashmir?

Option 1: Stand Up India Scheme

Option 2: Ujjwala Scheme

Option 3: AVSAR Scheme of the Airport Authority of India

Option 4: KUSUM Scheme

Team Careers360 17th Jan, 2024

Correct Answer: AVSAR Scheme of the Airport Authority of India


Solution : The correct answer is the AVSAR Scheme of the Airport Authority of India.

Lieutenant Governor Manoj Sinha inaugurated the "UMEED Market Place" at Srinagar International Airport in Jammu and Kashmir under the AVSAR Scheme by the Airport Authority

18 Views

Question : If the volume of a sphere is 38808 cm³, then its surface area is:

Option 1: 5554 cm²

Option 2: 5574 cm²

Option 3: 5564 cm²

Option 4: 5544 cm²

Team Careers360 21st Jan, 2024

Correct Answer: 5544 cm²


Solution : Volume of sphere (radius = $r$) = 38808 cm$^3$
Volume of sphere = $\frac{4}{3}\pi r^3$
Surface Area of sphere = $4\pi r^2$
Calculation:
⇒ $\frac{4}{3}\pi r^3$ = 38808
⇒ $\frac{4}{3}\times\frac{22}{7}\times r^3$ = 38808
⇒ $r^3$ = $\frac{38808\times21}{88}$
⇒ $r^3$ = 9261
⇒ $r$ =

The question have been saved in answer later, you can access it from your profile anytime. Access now