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Hi Aman,
This is the solution.
Each wiper sweeps a sector of a circle. Radius $r=25 \mathrm{~cm}$, angle $=150^{\circ}$ Area cleaned by one wiper $ =\frac{150}{360} \pi r^2=\frac{5}{12} \pi(25)^2=\frac{3125 \pi}{12} \mathrm{~cm}^2 $ Since two wipers do not overlap, Total cleaned area $ =2 \times \frac{3125 \pi}{12}=\frac{3125 \pi}{6} \mathrm{~cm}^2 \approx 1636
You can check the JEE Mains rank predictor on our website to get an idea about the college admissions with less score.
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For the 2026 JEE Advanced, OBC-NCL candidates require a JEE Main percentile of 75+ to qualify. If you aim for an 80+ percentile, that will give you a safer margin for qualification.
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Yes. Please find the CBSE grade 10 question papers by clicking on CBSE Class 10 Previous Year Question Papers PDF: Download Last Year Sample Papers
Based on NIRF 2025 ranking, the best colleges in Maharashtra are:
First, you need to clarify the exam in which you got 72 percentile with general category. If you're talking about JEE Main examination, you can expect your rank between 3,00,00 - 3,75,00. WIth this much rank, you can admission into colleges like Assam University , Galgotias University, and others.
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Hi Barnali, please check NIT Rourkela cutoff JEE Main 2026 to know about the percentile cutoff for general EWS category.
Dear Student,
Please check: IIT JAM 2026: Answer Key (Out), Question Paper, Result, Cutoff, Score Vs College
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