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Question : If a sum of Rs. 12,500 is invested for 1 year at 12% per annum interest is compounded semi-annually, then the interest earned is:
Option 1: Rs. 1,505
Option 2: Rs. 1,535
Option 3: Rs. 1,545
Option 4: Rs. 1,550
Correct Answer: Rs. 1,545
Solution : Given: Principal = Rs. 12,500 Rate of Interest = 12% Time = 1 year Formula used: Amount = $P(1+\frac{\frac{R}{2}}{100})^{2n}$ where n is the time in years and $R$ is rate of interest per annum when compounded half-yearly. CI = $P(1+\frac{\frac{R}{2}}{100})^{2n} - P$ $\therefore n
Question : Select the most appropriate synonym of the given word. Bewilderment
Option 1: Confusion
Option 2: Agreement
Option 3: Arrangement
Option 4: Settlement
Correct Answer: Confusion
Solution : The first option is the correct answer.
"Bewilderment" refers to a feeling of being perplexed or puzzled, often resulting from encountering a complex or confusing situation. On the other hand, "confusion" is a more general term encompassing a state of uncertainty, disarray, or a lack
Question : The sum of the squares of 3 consecutive positive numbers is 365. The sum of the numbers is:
Option 1: 30
Option 2: 33
Option 3: 36
Option 4: 45
Correct Answer: 33
Solution : Let the consecutive numbers be (x – 1), x and (x + 1). According to the question, (x–1)2 + x2 + (x+1)2 = 365 ⇒ (x2 – 2x + 1) + x2 + (x2 + 2x + 1) =
Question : Select the most appropriate synonym of the given word. Miscellaneous
Option 1: Various
Option 2: Contemporary
Option 3: Virtuous
Option 4: Interesting
Correct Answer: Various
Solution : The correct choice is the first option.
Miscellaneous refers to a collection or mixture of different kinds of things. Similarly, various denotes a variety of different types of things. In the context of the options provided, various is the closest synonym to "miscellaneous", as
Question : If the radii of two circles are 6 cm and 3 cm and the length of the transverse common tangent is 8 cm, then the distance between the two centres is:
Option 1: $\sqrt{145} \text{ cm}$
Option 2: $\sqrt{140} \text{ cm}$
Option 3: $\sqrt{150} \text{ cm}$
Option 4: $\sqrt{135} \text{ cm}$
Correct Answer: $\sqrt{145} \text{ cm}$
Solution : The distance between the centres of two circles with radii $r_1$ and $r_2$ (with $r_1 > r_2$), and the length of the transverse common tangent $t$, $d = \sqrt{t^2 + (r_1 + r_2)^2}$ Substituting the given values into the equation: $d = \sqrt{8^2
Question : If $x+\frac{1}{x}=2$, then the value of $x^{11}+\frac{1}{x^{20}}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 7
Correct Answer: 2
Solution : Given, $x+\frac{1}{x}=2$ ⇒ $x^2+1=2x$ ⇒ $x^2+1-2x=0$ ⇒ $(x-1)^2=0$ ⇒ $x-1=0$ $\therefore x=1$ Consider, $x^{11}+\frac{1}{x^{20}}$ = $1^{11}+\frac{1}{1^{20}}$ = $1+1$ = $2$ Hence, the correct answer is 2.
Question : Directions: Which of the following letter clusters will replace the question mark (?) in the given series to make it logically complete? AZX, CBZ, EDB, GFD, ?
Option 1: IHF
Option 2: IFH
Option 3: FHI
Option 4: JHF
Correct Answer: IHF
Solution : Given: AZX, CBZ, EDB, GFD, ?
In the above-given series, add 2 to the place value of each letter of the previous term to obtain the next term. AZX→A + 2 = C; Z + 2 = B; X + 2 = Z CBZ→C +
Question : Which Indian tabla virtuoso and musician won the "Best Contemporary World Music Album Grammy Award" for "Global Drum Project"?
Option 1: Pandit Sandeep Das
Option 2: Ustad Alla Rakha
Option 3: Ustad Zakir Hussain
Option 4: Pandit Anindo Chatterjee
Correct Answer: Ustad Zakir Hussain
Solution : The correct option is Ustad Zakir Hussain.
The Indian tabla virtuoso and musician who won the "Best Contemporary World Music Album Grammy Award" for "Global Drum Project" is Zakir Hussain. He shared this Grammy Award with Mickey Hart, Sikiru Adepoju, and Giovanni
Question : If $\sec\theta+\tan\theta=5$, then find the value of $\tan\theta$.
Option 1: $\frac{5}{12}$
Option 2: $\frac{13}{5}$
Option 3: $\frac{13}{3}$
Option 4: $\frac{12}{5}$
Correct Answer: $\frac{12}{5}$
Solution : Given: $\sec\theta+\tan\theta=5$--------------------(equation 1) We know, $\sec^2\theta-\tan^2\theta=1$ ⇒ $(\sec\theta+\tan\theta)(\sec\theta-\tan\theta)=1$ ⇒ $(5)(\sec\theta-\tan\theta)=1$ ⇒ $(\sec\theta-\tan\theta)=\frac{1}{5}$----------------------(equation 2) Now, solving equations 1 and 2 we get, $\tan\theta=\frac{12}{5}$ Hence, the correct answer is $\frac{12}{5}$.
Question : Which one of the following Committee Reports recommended the establishment of the Institutions of Lokpal and Lokayukta?
Option 1: First Administrative Reforms Committee
Option 2: Gorwala Report
Option 3: Ashok Mehta Committee
Option 4: The Appleby Reports
Correct Answer: First Administrative Reforms Committee
Solution : The correct option is the First Administrative Reforms Committee
In 1966, the Morarji Desai-led Administrative Reforms Commission (ARC) delivered an interim report titled "Problems of Redressal of Citizen's Grievances." To resolve citizens' complaints, ARC recommended the establishment of two special authorities known
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