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Question : The number 76050 is NOT divisible by which of the following numbers?
Option 1: 4
Option 2: 9
Option 3: 3
Option 4: 13
Correct Answer: 4
Solution : The prime factors of 76050 are 2, 3, 5, and 13. 76050 = 21 × 32 × 52 × 132 So, 76050 is not divisible by 4 out of the given options. Hence, the correct answer is 4.
Question : In our country the 'Van Mahotsav' day is observed on
Option 1: 10th August
Option 2: 1st July
Option 3: 2nd October
Option 4: 1st December
Correct Answer: 1st July
Solution : The correct answer is 1st July.
Van Mahotsav Day is celebrated every year in the first week of July that is, from July 1 to July 7. It was initiated in 1950 by K. M. Munshi, then Union Minister of Agriculture and Food, to
Question : Directions: In the following question, the given sentence has four parts marked P, Q, R, and S. Choose the part of the sentence with the error and select it as your answer. If there is no error, select "No Error (S)" as your answer.
(P) The old man (Q) told his sons (R) that there was no such thing like luck. (S) No Error
Option 1: 1
Option 2: 2
Option 4: 4
Correct Answer: 3
Solution : The error is in part (R) marked by the third option.
Explanation:
In this sentence, "such as" is used instead of "like" to convey the idea that luck is an example or type of thing, rather than a similarity. Such as is used for giving
Question : The climatic zones are classified on the basis of
Option 1: distance from equator
Option 2: elevation
Option 3: rainfall
Option 4: distance from the sea
Correct Answer: rainfall
Solution : The correct option is - rainfall
The maximum and minimum temperatures, temperature range, total and seasonal distribution of precipitation, and other factors are used to classify the climatic zones. The most well-known classification scheme was initially created by Wladimir Koppen based on these parameters.
Question : If, $\frac{r}{13}+\frac{13}{r}=1$, then the value of $r^3$ is:
Option 1: –2157
Option 2: 2197
Option 3: 2157
Option 4: –2197
Correct Answer: –2197
Solution : $\frac{r}{13}+\frac{13}{r}=1$ We know that if $x+\frac{1}{x} = 1$, then $x^3 = -1$ Let $\frac{r}{13} = x$ The equation becomes, $x+\frac{1}{x} = 1$ ⇒ $x^2-x+1=0$ $x^3+1^3=(x+1) (x^2-x+1)$ ⇒ $x^3+1^3 =0$ ⇒ $x^3 = -1$ ⇒ $(\frac{r}{13})^3 = -1$ ⇒ $r^3 = -2197$ Hence, the correct answer
Question : If $x+y=2z$, then the value of $\frac{x}{x-z}+\frac{z}{y-z}$ is:
Option 1: $1$
Option 2: $3$
Option 3: $\frac{1}{2}$
Option 4: $2$
Correct Answer: $1$
Solution : Given: $x+y = 2z$ Now, $\frac{x}{x-z}+\frac{z}{y-z}$ $= \frac{x(y-z)+z(x-z)}{(x-z)(y-z)}$ $= \frac{xy−xz+zx−z^2}{xy−xz−zy+z^2}$ $= \frac{xy−z^2}{xy−z(x+y)+z^2}$ $= \frac{xy−z^2}{xy−z(2z)+z^2}$ $= \frac{xy−z^2}{xy−z^2}$ $= 1$ Hence, the correct answer is $1$.
Question : P, Q, and R are partners and invest in a business. P invests $\frac{1}{5}^{th}$ of total investments and Q invests $\frac{1}{4}^{th}$ of the total investments. What is the ratio of investments of P, Q, and R respectively?
Option 1: 4 : 8 : 11
Option 2: 4 : 5 : 11
Option 3: 4 : 7 : 11
Option 4: 4 : 5 : 9
Correct Answer: 4 : 5 : 11
Solution : P invests $\frac{1}{5}$th of the total investment. Q invests $\frac{1}{4}$th of the total investment. Taking, LCM (4, 5) = 20 Let the total investment be Rs. 20 P invests $\frac{1}{5}$th of the total investment = $\frac{1}{5}\times 20$ = Rs. 4 Q
Question : Which of the following elements has an atomic number greater than that of fluorine?
Option 1: Sodium
Option 2: Beryllium
Option 3: Nitrogen
Option 4: Boron
Correct Answer: Sodium
Solution : The correct option is Sodium
Sodium is an element with a higher atomic number than fluorine. Sodium has an atomic number of 11 and Fluorine's atomic number is 9.
Question : The LCM of 96, 132, and 438 is:
Option 1: 86084
Option 2: 67055
Option 3: 85046
Option 4: 77088
Correct Answer: 77088
Solution : The prime factorization of the given numbers is: $96 = 2^5 \times 3 $ $132 = 2^2 \times 3^1 \times 11^1 \\$ $438 = 2^1 \times 3^1 \times 73^1$ Now, identify the highest powers of each prime factor: It is $2^5$,$3^1$,$11^1$, and $73^1$ Multiply these
Question : The enormous amount of energy released in the explosion of an atomic bomb is due to the
Option 1: Conversion of mass into energy
Option 2: Conversion of chemical energy into heat energy
Option 3: Conversion of mechanical energy into nuclear energy
Option 4: Conversion of neutrons into protons
Correct Answer: Conversion of neutrons into protons
Solution : The correct answer is the Conversion of neutrons into protons.
The release of an enormous amount of energy in an atomic bomb explosion is caused by the conversion of neutrons into protons. When a neutron collides with the nucleus of
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