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Question : Directions: Study the graph and answer the question. What was the approximate percentage drop in the sale of Pep-up in 1990 over its sale in 1989?
Option 1: 5%
Option 2: 14%
Option 3: 12%
Option 4: 20%
Correct Answer: 14%
Solution : Given: Sales of Pep-up in the year 1989 = 35 lakh Sales of Pep-up in the year 1990 = 30 lakh Percentage change = $\frac{\text{Sales of Pep-up in 1989 - Sales of Pep-up in 1990}}{\text{Sales of Pep-up in 1989}}\times100$ Percentage change = $\frac{\text{35–30}}{\text{35}}\times100$ Percentage change
Question : In what ratio should sugar costing Rs. 40 per kg be mixed with sugar costing Rs. 48 per kg to earn a profit of 20% by selling the mixture at Rs. 54 per kg?
Option 1: 3 : 5
Option 2: 4 : 7
Option 3: 5 : 8
Option 4: 2 : 3
Correct Answer: 3 : 5
Solution :
The cost price of the mixture $=\frac{100}{100+20}×54=\frac{100}{120}×54=45$ Using the rule of alligation, we get the desired ratio. (48 – 45) : (45 – 40) = 3 : 5 Hence, the correct answer is 3 : 5.
Question : If (a – b) = 1, what is the value of (a3 – b3)?
Option 1: a2 + ab + b2
Option 2: (a + b)2 + 3ab
Option 3: a2 – ab + b2
Option 4: a2 + 2ab + b2
Correct Answer: a2 + ab + b2
Solution : Given: a – b = 1 We know the algebraic identity, a3 – b3 = (a – b)(a2 + ab + b2) Substitute the given value in the above formula and we get, ⇒
Question : If the HCF of xy3, x2 y, and x3 y4 is xy, then their LCM is________.
Option 1: x3 y4
Option 2: x3 y3
Option 3: x4 y3
Option 4: x4 y4
Correct Answer: x3 y4
Solution : In xy3, x2 y, and x3 y4 The highest power of x = 3 The highest power of y = 4 ⇒ LCM = x3 y4 Hence, the correct answer is x3 y4
Question : Directions: Select the option that is related to the third number in the same way as the second number is related to the first number and the sixth number is related to the fifth number. 6 : 43 :: 11 : ? :: 4 : 21
Option 1: 122
Option 2: 133
Option 3: 110
Option 4: 128
Correct Answer: 133
Solution : Given: 6 : 43 :: 11 : ? :: 4 : 21
Like, 6 : 43→{6 × (6 + 1)} + 1 = {6 × 7} + 1 = 42 + 1 = 43 And, 4 : 21→{4 × (4 + 1)} + 1 =
Question : When was the Prime Minister’s Employment Generation Programme (PMEGP) launched?
Option 1: 2006
Option 2: 2008
Option 3: 2012
Option 4: 2009
Correct Answer: 2008
Solution : The correct answer is 2008.
Prime Minister's Employment Generation Programme (PMEGP) was announced in August 2008. This is a credit-linked scheme of the Government of India. The scheme is formed by merging the Rural Employment Generation Programme (REGP) and Pradhan Mantri Rojgar Yojana (PMRY).
Question : What is the smallest three-digit number which, when divided by 8 or 6, leaves a remainder of 1 in each case?
Option 1: 121
Option 2: 119
Option 3: 123
Option 4: 125
Correct Answer: 121
Solution : Given, The smallest 3-digit number leaves 1 remainder when divided by 8 or 6. 8 = 2 × 2 × 2 6 = 3 × 2 ⇒ LCM of 8 and 6 = 2 × 2 × 2 × 3 = 24 When we divide
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
You should learn to adopt (1) / yourself to the (2) / changing circumstances.(3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The error lies in the first part of the sentence.
The reason for the error is the incorrect use of the word "adopt" when it should be "adapt". "Adapt" means to adjust or change according to the changing circumstances, while "adopt" means to take something
Question : The value of $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$ is:
Option 1: $\frac{1}{2}$
Option 2: $2\frac{1}{2}$
Option 3: $3\frac{1}{2}$
Option 4: $9\frac{1}{2}$
Correct Answer: $\frac{1}{2}$
Solution : $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} -\frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$ $=3\frac{1}{2} -[2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(\frac{3}{2}-\frac{1}{2})]$ $=3\frac{1}{2} -[2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}\times 1]$ $=3\frac{1}{2} -[\frac{9}{4}+\frac{5}{4} - \frac{1}{2}]$ $=3\frac{1}{2} -[\frac{14}{4} - \frac{1}{2}]$ $=3\frac{1}{2} -[\frac{12}{4}]$ $=\frac{7}{2} -3$ $=\frac{1}{2}$ Hence, the correct answer is $\frac{1}{2}$.
Question : A light wave is incident over a plane surface with velocity x. After reflection, the velocity becomes:
Option 1: x/2
Option 2: x
Option 3: 2x
Option 4: x/4
Correct Answer: x
Solution : The correct option is x.
When a light wave is incident on a plane surface, its velocity remains unchanged after reflection. The speed of light is determined by the properties of the medium it is travelling through. In a uniform medium, like air, the velocity
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