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Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
ABILITY : LIBAYTI :: CHRONIC : ORHCCIN :: HEAVILY : ?

Option 1: VAEHYLI

Option 2: HAVIEYL

Option 3: AEVHLYI

Option 4: LYIAVHE

Team Careers360 27th Jan, 2024

Correct Answer: VAEHYLI


Solution : Given:
ABILITY : LIBAYTI 
CHRONIC : ORHCCIN
HEAVILY : ?

Here, ABILITY→ABIL/ITY
CHRONIC→CHRO/NIC
The logic used here is –

Let us apply the same to the word HEAVILY→HEAV/ ILY

So, HEAVILY can be coded as VAEHYLI. Hence, the first option is correct.

92 Views

Question : Directions: Select the option that represents the letters that, when sequentially placed from left to right in the blanks below, will complete the letter series.
P_ _MO_ST_OP_TM_ _S _MO

Option 1: STPMSOPT

Option 2: TSSMPOPT

Option 3: STSMPOPT

Option 4: STPSMOPT

Team Careers360 27th Jan, 2024

Correct Answer: STPMSOPT


Solution : Given:
P_ _MO_ST_OP_TM_ _S _MO

To fill the series we have to divide the series : P_ _MO / _ST_O / P_TM_ / _S _MO 
Let's check each option.
First option: STPMSOPT; PSTMO / PSTMO / PSTMO

17 Views

Question : Directions: In a certain code language, APPLES is written as AQQMET. How will ORANGE be written in that language?

Option 1: SOCHEI

Option 2: OSAOHE

Option 3: OSAHOE

Option 4: SOACHE

Team Careers360 27th Jan, 2024

Correct Answer: OSAOHE


Solution : Given:
APPLES is coded as AQQMET.

Add 1 in the place value of the consonants and write the vowels as it is of APPLES, to obtain the required code –
A = A; P + 1 = Q; P + 1 = Q; L +

24 Views

Question : Select the most appropriate ANTONYM of the given word.

Rabble

Option 1: Rubbish

Option 2: Havoc

Option 3: Noise

Option 4: Elite

Team Careers360 26th Jan, 2024

Correct Answer: Elite


Solution : The correct choice is the fourth option.

Rabble refers to a disorderly crowd, a mass of ordinary people, or the common populace. On the other hand, the elite represents a select or superior group in society, often distinguished by wealth, power, or talent.

The

13 Views

Question : Which state among the following has the largest reserves of gold ore in India as of 2021?

Option 1: Jharkhand

Option 2: Rajasthan

Option 3: Bihar

Option 4: Karnataka

Team Careers360 27th Jan, 2024

Correct Answer: Bihar


Solution : The correct option is Bihar.

According to a survey conducted by the Geological Survey of India, the Jamui district in Bihar holds a significant gold reserve, totaling approximately 222.88 million metric tonnes, which includes 27.6 metric tonnes of mineral-rich ore. In terms of primary gold

13 Views

Question : The Aryans succeeded in their conflicts with the pre - Aryans because

Option 1: they used elephants on a large scale

Option 2: they were taller and stronger

Option 3: they were from an advanced urban culture

Option 4: they used chariots driven by horses

Team Careers360 27th Jan, 2024

Correct Answer: they used chariots driven by horses


Solution : The Correct Answer is they used chariots driven by horses

Because they had superior Bronze and Iron tools and ox- and horse-drawn carts with light spoked wheels, Aryans were more successful than pre-Aryans. In order to create a new civilization,

182 Views

Question : A cuboidal water tank is 12 m long, 9 m wide and 7.5 m deep. How many litres of water can it hold?

Option 1: 840000

Option 2: 805000

Option 3: 780000

Option 4: 810000

Team Careers360 26th Jan, 2024

Correct Answer: 810000


Solution : Given:
Length = 12 m, Breadth = 9 m, Height = 7.5 m
Volume of cube = Length × Breadth × Height
⇒ Volume of cube = 12 × 9 × 7.5 = 810 m3
The amount of water held by 1 m3

19 Views

Question : Two chords AB and CD of a circle with centre O intersect at P. If $\angle$ APC = 40º, then the value of $\angle$AOC + $\angle$BOD is:

Option 1: 50º

Option 2: 60º

Option 3: 80º

Option 4: 120º

Team Careers360 26th Jan, 2024

Correct Answer: 80º


Solution :
The angle subtended by a chord at the centre is twice the angle subtended on the circumference. 
$\angle$BOD = 2$\angle$BCD
⇒ $\angle$AOC = 2$\angle$ABC
⇒ $\angle$AOC + $\angle$BOD = 2($\angle$BCD + $\angle$ABC)
The sum of the interior angle is equal to the exterior angle.
$\angle$BCD

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