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11 Views

Question : Simplify the following expression:
$\frac{\left(a^2+b^2-c^2\right)^2-\left(a^2-b^2+c^2\right)^2}{b^2-c^2}$

Option 1: $3a^2$

Option 2: $4a^2$

Option 3: $5a^2$

Option 4: $2a^2$

Team Careers360 10th Jan, 2024

Correct Answer: $4a^2$


Solution : Given: $\frac{(a^2+b^2-c^2)^2-(a^2-b^2+c^2)^2}{b^2-c^2}$
$= \frac{(a^2+b^2-c^2+a^2-b^2+c^2)(a^2+b^2-c^2-a^2+b^2-c^2)}{b^2-c^2}$
$= \frac{(2a^2)(2b^2-2c^2)}{b^2-c^2}$
$= \frac{4a^2(b^2-c^2)}{b^2-c^2}$
$= 4a^2$
Hence, the correct answer is $4a^2$.

9 Views

Question : Who became the first woman soldier in the Indian Army to have skydived from 10,000 feet?

Option 1: Lieutenant General Madhuri Kanitkar

Option 2: Lance Naik Manju

Option 3: Lieutenant General Rajshree Ramasethu

Option 4: Air Marshal Arti Sarin

Team Careers360 20th Jan, 2024

Correct Answer: Lance Naik Manju


Solution : The correct answer is Lance Naik Manju.

Lance Naik Manju, a member of the Indian Army's Army Service Corps stationed in Bengaluru, made history in 2019 as the first female soldier-skydiver to successfully parachute from a height of 10,000 feet. This remarkable achievement

39 Views

Question : A 1000-metre-long train is running at the speed of 72 km/hr. If it crosses a bridge in 85 seconds, then what is the length of the bridge?

Option 1: 800 metres

Option 2: 700 metres

Option 3: 950 metres

Option 4: 750 metres

Team Careers360 13th Jan, 2024

Correct Answer: 700 metres


Solution : A 1000-metre-long train is running at the speed of 72 km/hr.
In 85 seconds it crosses a bridge.
In 85 seconds the train travels = $\frac{72000}{3600}×85=1700$ metres
When the train crosses a bridge, the distance covered by the train is the sum of the

21 Views

Question : Directions: Select the figure that will replace the question mark (?) in the following figure series.

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 18th Jan, 2024

Correct Answer:


Solution : In the given figure, the following pattern is being followed –
1. In each alternative box that is in box 2 and box 4 a new letter or number is introduced in the centre of the box.
2. The element U changed its position from right

18 Views

Question : Orders and other instruments made and executed in the name of the President are to be authenticated:

Option 1: The Minister concerned

Option 2: By the President

Option 3: In such manner as may be specified in rules made by the President

Option 4: The Prime Minister

Team Careers360 24th Jan, 2024

Correct Answer: In such manner as may be specified in rules made by the President


Solution : The correct answer is In such manner as may be specified in rules made by the President.

Orders and other instruments crafted and executed in the name of the President of India

25 Views

Question : Cloud burst means

Option 1: formation of artificial rain

Option 2: abnormally heavy downpours of rain, associated with thunderstorms

Option 3: presence of scattered flakes of clouds in the sky

Option 4: sowing of seeds of a crop in a cloudy weather

Team Careers360 21st Jan, 2024

Correct Answer: abnormally heavy downpours of rain, associated with thunderstorms


Solution : The correct answer is abnormally heavy downpours of rain, associated with thunderstorms.

Cloudburst is an extreme weather phenomenon in which abnormally high rainfall is witnessed over a short period. It is often associated with hail and thunderstorms. Usually,

24 Views

Question : __________ was the first governor-general of Bengal.

Option 1: Warren Hastings

Option 2: William Bentinck

Option 3: Charles Metcalfe

Option 4: John Shore

Team Careers360 12th Jan, 2024

Correct Answer: Warren Hastings


Solution : The correct answer is Warren Hastings.

Warren Hastings was the first governor-general of Bengal from 1773 to 1785. He became the governor-general of Bengal by the Regulating Act of 1773, which brought the presidencies of Madras and Bombay under Bengal’s control.

19 Views

Question : If $\sec A=\frac{5}{4}$, then the value of $\frac{\tan A}{1+\tan ^2 A}-\frac{\sin A}{\sec A}$ is:

Option 1: 2

Option 2: 1

Option 3: 0

Option 4: 3

Team Careers360 14th Jan, 2024

Correct Answer: 0


Solution : $\sec A=\frac{5}{4}$
$\cos A = \frac{1}{\sec A} = \frac{4}{5}$
$\sin A = \sqrt{1-\cos^2A}=\sqrt{1-(\frac{4}{5})^2}=\frac{3}{5}$
$\tan A = \frac{\sin A}{\cos A}=\frac{3}{4}$
$\therefore$ $\frac{\tan A}{1+\tan ^2 A}-\frac{\sin A}{\sec A}$
$= \frac{\frac{3}{4}}{1+(\frac{3}{4})^2}-\frac{\frac{3}{5}}{\frac{5}{4}}$
$= \frac{3\times 4}{16+9}-\frac{3\times4}{5\times 5}$
$=\frac{12}{25}-\frac{12}{25}$
$=0$
Hence, the correct answer is 0.

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