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Question : The Merdeka Cup is associated with which of the following sports?
Option 1: Golf
Option 2: Hockey
Option 3: Chess
Option 4: Football
Correct Answer: Football
Solution : The correct option is Football.
Football is connected to the Merdeka Cup. Established in 1957, it is an international football competition. The term "Merdeka" in Malay means "independence". In the past, the Merdeka Cup has been a significant football competition in the area.
Question : Which is the IUPAC group prefix of Acyl halide compounds?
Option 1: Alkoxy Carbonyl
Option 2: Carbamoyl
Option 3: Cyano
Option 4: Halo Carbonyl
Correct Answer: Halo Carbonyl
Solution : The correct option is Halo Carbonyl.
An acyl halide group is represented with a prefix such as "Fluoro Carbonyl-", "Chloro carbonyl-", "Bromo carbonyl-" or "Iodo carbonyl-" when related to a substituting group or when another group is present that has priority for citation
Question : If $x+y+z=0$, then what is the value of $\frac{\left (3y^{2}+x^{2}+z^{2} \right )}{\left (2y^{2}-xz \right)}$?
Option 1: $2$
Option 2: $1$
Option 3: $\frac{3}{2}$
Option 4: $\frac{5}{3}$
Correct Answer: $2$
Solution : Given: $x+y+z=0$ Solution: $\frac{(3y^{2}+x^{2}+z^{2})}{(2y^{2}-xz)}$ Since $x+y+z=0$, put $x = 1$, $y = –1$ , $z = 0$; $=\frac{3+1}{2}= 2$ Hence, the correct answer is $2$.
Question : Directions: From the given alternative words, select the word that cannot be formed using the letters of the given word. MEASUREMENT
Option 1: TEAMS
Option 2: MASTER
Option 3: SUMMIT
Option 4: SUMMER
Correct Answer: SUMMIT
Solution : Given: MEASUREMENT
Now, let's compare all the option words with the word MEASUREMENT – First option: TEAMS; All the letters of the word TEAMS are present in the word MEASUREMENT. Second option: MASTER; All the letters of the word MASTER are present in the word
Question : A watch is listed for Rs. 230 and sold at a discount of 12%. The selling price of the watch is:
Option 1: Rs. 27.60
Option 2: Rs. 276
Option 3: Rs. 202.40
Option 4: Rs. 257.60
Correct Answer: Rs. 202.40
Solution : Marked Price = Rs. 230 Discount = 12% Selling Price = (100 – 12)% of 230 = 88% of 230 = $\frac{88 × 230}{100}$ = Rs. 202.40 Hence, the correct answer is Rs. 202.40.
Question : Direction: The bar diagram shows the monthly expenditure of a company. Study the graph and answer the question.
The fraction of money spent on refreshments is:
Option 1: $13\frac{1}{2}$
Option 2: $\frac{2}{27}$
Option 3: $\frac{1}{10}$
Option 4: $10$
Correct Answer: $\frac{2}{27}$
Solution : Total expenditure = (80 + 10 + 20 + 10 + 15) = Rs. 135 lakhs Total refreshment costs = Rs. 10 lakhs Required fraction = $\frac{\text{Expenditure on refreshments}}{\text{Total expenditure}}=\frac{10}{135}=\frac{2}{27}$ Hence, the correct answer is $\frac{2}{27}$.
Question : The practice of Sati was abolished under the Governor-Generalship of ____________.
Option 1: Lord Ellenborough
Option 2: Lord Metcalfe
Option 3: Lord Auckland
Option 4: Lord William Bentinck
Correct Answer: Lord William Bentinck
Solution : The correct option is Lord William Bentinck.
The practice of Sati, the ancient Indian custom where a widow self-immolates on her husband's funeral pyre, was officially abolished under the Governor-Generalship of Lord William Bentinck. He issued a regulation on December 4, 1829,
Question : Directions: In the following question a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. 1, 16, 81, 256, 625, ?
Option 1: 1225
Option 2: 4163
Option 3: 2225
Option 4: 1296
Correct Answer: 1296
Solution : Given: 1, 16, 81, 256, 625,?
Here, (1)4 = 1; (2)4 = 16; (3)4 = 81; (4)4 = 256; (5)4 = 625; (6)4 = 1296
So, the required term will be 1296. Hence, the fourth option is correct.
Question : If $x+ \frac{1}{x} =2$, then the value of $({x}^{99}+ \frac{1}{x^{99}} –2)$ is:
Option 1: –2
Option 2: 0
Option 3: 2
Option 4: 4
Correct Answer: 0
Solution : Given: $⇒x+ \frac{1}{x} =2$ By squaring both sides, $({x}+ \frac{1}{x})^{2} =({2})^{2}$ $⇒{x}^{2}+ \frac{1}{x^{2}}+2×x×\frac{1}{x} =4$ $⇒{x}^{2}+ \frac{1}{x^{2}}=2$ Similarly, we can find, $({x}+ \frac{1}{x})^{3} =({2})^{3}$ $⇒{x}^{3}+ \frac{1}{x^{3}}+3×x×\frac{1}{x}(x+ \frac{1}{x}) =8$ $⇒{x}^{3}+ \frac{1}{x^{3}}+3×2 =8$ $⇒{x}^{3}+ \frac{1}{x^{3}}=2$ Similarly, we can find the value of, $⇒{x}^{99}+ \frac{1}{x^{99}}=2$ $\therefore {x}^{99}+ \frac{1}{x^{99}} -2=0$
Question : Which of the following pairs contributed significantly to integrate the princely states into Indian Union ?
Option 1: Sardar Patel and Jawaharlal Nehru .
Option 2: Sardar Patel and V.P. Menon.
Option 3: Sardar Patel and Mahatma Gandhi .
Option 4: Sardar Patel and K.M. Munsi .
Correct Answer: Sardar Patel and V.P. Menon.
Solution : The correct answer is Sardar Patel and V P Menon.
Sardar Vallabhbhai Patel was the first Home minister of India and he played a pivotal role in the integration of princely states in the Indian union. As a member of constituent
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