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Question : What is the area of a triangle having a perimeter of 32 cm, one side of 11 cm, and the difference between the other two sides is 5 cm?

Option 1: $8\sqrt{30}$ cm2

Option 2: $5\sqrt{35}$ cm2

Option 3: $6\sqrt{30}$ cm2

Option 4: $8\sqrt{2}$ cm2

Team Careers360 25th Jan, 2024

Correct Answer: $8\sqrt{30}$ cm2


Solution : Let the sides of the triangle be $a$, $b$, and $c$.
Given Perimeter = 32 cm
⇒ $a+b+c=32$ ...... equation (1)
One side, let $a$ =11 cm
Also, the difference between the other two sides, $b−c=5$........ equation (2)
Performing equation (1) + equation

8 Views

Question : Directions: Which of the following interchange of signs would make the given equation correct?
13 + 26 × 2 – 5 ÷ 4 = 6

Option 1: ÷ and +

Option 2: + and –

Option 3: × and –

Option 4: × and ÷

Team Careers360 25th Jan, 2024

Correct Answer: × and ÷


Solution : Given:
13 + 26 × 2 – 5 ÷ 4 = 6

Replace the given symbols in the options one by one with the original symbols in the given equation.
First option: ÷ and +
= 13 ÷ 26 × 2 – 5

13 Views

Question : Select the INCORRECTLY spelt word.

Option 1: Difficulty

Option 2: Thesaurus

Option 3: Dictionary

Option 4: Dinoshauraus

Team Careers360 25th Jan, 2024

Correct Answer: Dinoshauraus


Solution : The correct option is the fourth option.

Explanation:
The correct spelling of the word is dinosaur. Dinosaurs are a group of extinct reptiles that lived millions of years ago. They varied greatly in size, shape, and habitat and are known for their dominance on Earth

3 Views

Question : Find out the area of the triangle of base 7 cm and the corresponding height of 12 cm.

Option 1: 42 cm2

Option 2: 54 cm2

Option 3: 43 cm2

Option 4: 44 cm2

Team Careers360 25th Jan, 2024

Correct Answer: 42 cm2


Solution : Area of a triangle = $\frac{1}{2}$ ​× Base × Height
Given the base ($b$) is 7 cm and the height ($h$) is 12 cm.
So, the area = $\frac{1}{2}$ ​× 7 × 12 = 42 cm2
Hence, the correct answer is 42

42 Views

Question : Directions: What will come in the place of the question mark (?) in the following equation if + and – are interchanged and × and ÷ are interchanged?
49 × 7 ÷ 13 – 87 + 12 = ?

Option 1: 167

Option 2: 166

Option 3: 159

Option 4: 171

Team Careers360 25th Jan, 2024

Correct Answer: 166


Solution : Given:
49 × 7 ÷ 13 – 87 + 12 = ?

On, interchanging the symbols with each other, we get –
= 49 ÷ 7 × 13 + 87 – 12
= 7 × 13 + 87 – 12
= 91 + 87 –

16 Views

Question : Simplify the following expression: $\frac{1-\sin A}{\cos A}+\frac{\cos A}{1-\sin A}$

Option 1: $2 \cos A$

Option 2: $2 \tan A$

Option 3: $2 \sec A$

Option 4: $2 \sin A$

Team Careers360 25th Jan, 2024

Correct Answer: $2 \sec A$


Solution : $\frac{1-\sin A}{\cos A}+\frac{\cos A}{1-\sin A}$
$=\frac{(1-\sin A)^2+\cos^2A}{\cos A(1-\sin A)}$
$=\frac{1+\sin^2 A-2\sin A+\cos^2A}{\cos A(1-\sin A)}$
$=\frac{1+1 -2\sin A}{\cos A(1-\sin A)}$
$=\frac{2 -2\sin A}{\cos A(1-\sin A)}$
$=\frac{2(1 -\sin A)}{\cos A(1-\sin A)}$
$=\frac{2}{\cos A}$
$=2\sec A$
Hence, the correct answer is $2\sec A$.

15 Views

Question : A is twice as fast as B and B is thrice as fast as C. The journey covered by C in $1\frac{1}{2}$ hour will be covered by A in:

Option 1: 15 minutes

Option 2: 30 minutes

Option 3: 1 hour

Option 4: 10 minutes

Team Careers360 25th Jan, 2024

Correct Answer: 15 minutes


Solution : Given: A is twice as fast as B and B is thrice as fast as C. The journey is covered by C in $1\frac{1}{2}$ hour.
Let the speed of C be $x$ metre/min.
So, the speed of B will be $3x$ metre/min.
And the

16 Views

Question : The Chhatrapati Shivaji Maharaj Terminus was formerly known as ______.

Option 1: Elizabeth Terminus Station

Option 2: James Terminus Station

Option 3: George Terminus Station

Option 4: Victoria Terminus Station

Team Careers360 25th Jan, 2024

Correct Answer: Victoria Terminus Station


Solution : The correct answer is Victoria Terminus Station.

The Chhatrapati Shivaji Terminus touches the Arabian Sea coast and is located in Mumbai, in Western India. The Victoria Terminus Station was the previous name of the Chhatrapati Shivaji Maharaj Terminus. It is one of

28 Views

Question : Which of the following chemicals is used as a preservative to slow browning and discolouration in foods and beverages during preparation, storage, and distribution?

Option 1: Nitrous oxide

Option 2: Phosgene

Option 3: Sulphites

Option 4: Chlorine

Team Careers360 25th Jan, 2024

Correct Answer: Sulphites


Solution : The correct answer is Sulphites.

Sulphites is a sulphur-containing compound that has been used for centuries to prevent discolouration and slow browning during the storage and distribution of many foods. When some fruits are cut, the exposure of the flesh to oxygen results in

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