It's a Question of your Career!

Correct Answer: from

Solution : The second option is the correct answer.

From is the correct preposition that indicates the starting point of something, and it fits perfectly in the sentence, conveying the meaning that the examination starts from the following week.

Therefore, the complete sentence is: The examination will

Correct Answer: 32.72 km/hr

Solution : According to the question
 First stretch at 20 km/hr:
⇒ Time t₁ = $\frac{2 km}{20km/hr}=\frac{1}{10}$ hr
 Second stretch 40 km/hr:
⇒ Time t₂ = $\frac{2km}{40km/hr}=\frac{1}{20}$ hr
 Third stretch 60km/hr:
⇒ Time t₃ = $\frac{2km}{60km/hr}=\frac{1}{30}$ hr
⇒ Total time = $\frac{1}{10} +

Correct Answer: 21

Solution : Given: 3 × [{(11 – 3) ÷ ($\frac{1}{2}$) of 8} + 15 ÷ 3]
= $3 × [\left \{8÷ 4 \right \}+ 15 ÷ 3]$
= $3 × [{2} + \frac{15}{3}]$
= $3 × [2 + 5]$
= $3 × 7$
= $21$
Hence, the

Correct Answer: Sir Frank Whittle

Solution : The correct answer is Sir Frank Whittle

The jet engine is attributed to Frank Whittle. British engineer Whittle submitted a patent application for his creation in 1930. The air was compressed in Whittle's engine using a centrifugal compressor. The first engine to undergo

Correct Answer: 4, 5, 6, 2 3, 1

Solution : Given:
E = 1, Z = 2, L = 3, P = 4, U = 5, Z = 6

Let's check each option –
First option: 4, 5, 1, 6, 2, 3→PUEZZL
Second option: 6,1, 4, 3, 5, 2→ZEPLUZ
Third

Correct Answer: Article 55

Solution : The correct answer is Article 55

The process to elect the President is outlined in Article 55 of the Constitution. A minimum of fifty electors must support a presidential nomination as proposers and an additional fifty electors as seconders. Depending on various electoral formulas,

Correct Answer: GMV

Solution : Given:
CAB, DDG, EGL, FJQ, ?

Add the consecutive odd numbers to the place value of each letter of the previous term to get the next term in the series –
CAB→C + 1 = D; A + 3 = D; B + 5 =

Correct Answer: 4270.4 cm²

Solution : The curved surface area of a cylinder with radius $r$ and height $h$ is $2\pi rh$.
Given, radius($r$) = 20 cm and height($h$) = 34 cm
So, the curved surface area of the cylinder
= $2\pi rh$
= 2 × 3.14 × 20

Correct Answer: $\frac{69}{4}$

Solution : Given: $1-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$
= $1-3 \div 12+(4 \div 1) \div 8+\left(4 \times 8 \times4\right) \times \frac{1}{8}$
= $1-\frac{3}{12}+\frac{4}{8}+\left(4 \times 8 \times4\right) \times \frac{1}{8}$
= $1-\frac{1}{4}+\frac{1}{2}+16$
= $\frac{4-1+2+64}{4}$
= $\frac{69}{4}$
Hence,

Correct Answer: Rs. 30,000

Solution : We have,
$R = 20\%$, and $T = 2$.
Let the principal be Rs. $P$.
When interest is compounded annually,
$\text{Compound interest} = P[(1 + \frac{R}{100})^{t}-1]$
$CI=P[(1+\frac{20}{100})^2-1]$
$CI=P[(\frac{6}{5})^2-1]=\frac{11P}{25}$
When the interest is compounded half-yearly,
$CI=P[(1+\frac{10}{100})^4-1]$
$CI=P[(\frac{11}{10})^2-1]$
$CI=P[(\frac{14641}{10000})-1]=\frac{4641P}{10000}$
From the question,
$⇒\frac{4641P}{10000}-\frac{11P}{25}=723$
$⇒\frac{4641P-4400P}{10000}=723$
$⇒\frac{241P}{10000}=723$
$⇒P