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Question : Two trains A and B start running at 80 km/hr and 82 km/hr towards each other from two different stations. They meet after 1 hour and 30 minutes. How far were they from each other when they started?
Option 1: 190 km
Option 2: 262 km
Option 3: 243 km
Option 4: 224 km
Correct Answer: 243 km
Solution : Relative speed = 80 + 82 = 162 km/hr Time taken = 1 hr 30 minutes = $\frac{3}{2}$ hr $\therefore$ Distance = 162 × $\frac{3}{2}$ = 243 km Hence, the correct answer is 243 km.
Question : Study the graph and answer the question. The number of workers in the factory whose daily wages are INR 450 or more but less than INR 600 is___________.
Option 1: 148
Option 2: 170
Option 3: 190
Option 4: 180
Correct Answer: 180
Solution : The number of workers in the factory whose daily wages are INR 450 or more but less than INR 600 = 50 + 58 + 72 = 180 Hence, the correct answer is 180.
Question : In the Indian Judicial system, PIL stands for _______.
Option 1: Public Interest Litigation
Option 2: Periodic Individual Litigation
Option 3: Private Interest License
Option 4: Periodic Interest Litigation
Correct Answer: Public Interest Litigation
Solution : The correct answer is Public Interest Litigation.
PILs, or public interest lawsuits, are lawsuits filed to protect the public interest and show that people from socially disadvantaged backgrounds can obtain justice. Public interest litigation (PIL) refers to legal action brought in a
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
He was elected (1) / as chairman (2) / of the college. (3) / No Error (4)
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : The correct choice is the second option.
"The" should be used before a designation or post, which can be given to only one person.
Therefore, the correct sentence is: He was elected as the chairman of the college.
Question : The value of $[ \frac{(0.337+0.126)^{2}-(0.337-0.126)^{2}}{0.337\times 0.126} ]$ is:
Option 1: 4
Option 2: 0.211
Option 3: 0.463
Option 4: 0.4246
Correct Answer: 4
Solution : Consider, $[ \frac{(0.337+0.126)^{2}-(0.337-0.126)^{2}}{0.337\times 0.126}]$ We know, $a^2-b^2=(a-b)(a+b)$ Here, $a=\small(0.337+0.126)$ and $b=\small(0.337-0.126)$ $=\frac{((0.337+0.126)-(0.337-0.126))((0.337+0.126)+(0.337-0.126))}{0.337\times 0.126}$ $=\frac{(2\times0.126)(2\times0.337)}{0.337\times 0.126}$ $=2\times2$ $= 4$ Hence, the correct answer is 4.
Question : Directions: Select the option that is related to the third number in the same way as the first number is related to the second number and the fifth number is related to the sixth number. 46 : 93 :: 38 : ? :: 58 : 117
Option 1: 83
Option 2: 77
Option 3: 81
Option 4: 79
Correct Answer: 77
Solution : Given: 46 : 93 :: 38 : ? :: 58 : 117
Multiply the first number by 2 and then add 1 to the resultant, to get the second number – Like, 46 : 93→46 × 2 + 1 = 93 And, 58 : 117→58
Question : A set of equations involving the electric and magnetic fields, and their sources, charges and current strengths, they ____________ are known as the equation.
Option 1: Einstein
Option 2: Dawn
Option 3: Newton
Option 4: Maxwell
Correct Answer: Maxwell
Solution : The correct answer is Maxwell.
The set of equations involving the electric and magnetic fields and their sources, charges, and current strengths is known as Maxwell's equations. Maxwell's equations are a set of four fundamental equations that form the foundation of classical electromagnetism.
Question : If $x+y=25$ and $x y=20$, then find the value of $x^3+y^3$.
Option 1: 13152
Option 2: 13125
Option 3: 14125
Option 4: 14152
Correct Answer: 14125
Solution : Given: $x+y=25$ and $xy=20$ We know that $(x+y)^{3}=x^{3}+y^{3}+3xy(x+y)$ Putting the given values, we have, ⇒ $(25)^{3}=x^{3}+y^{3}+3×20×(25)$ ⇒ $15625=x^{3}+y^{3}+1500$ ⇒ $x^{3}+y^{3}=15625–1500$ ⇒ $x^{3}+y^{3}=14125$ Hence, the correct answer is 14125.
Question : Find the area of the Kite whose diagonals are 22 cm and 6 cm.
Option 1: 66 cm2
Option 2: 100 cm2
Option 3: 88 cm2
Option 4: 50 cm2
Correct Answer: 66 cm2
Solution : Given: Diagonals of a kite are 22 cm and 6 cm. The area of the kite = $\frac{\text{Diagonal_1 × Diagonal_2}}{2}=\frac{22×6}{2}=66\ \text{cm}^2$ Hence, the correct answer is 66 cm2.
Question : If the volume of a cube is 729 cm3, then find the total surface area of the cube.
Option 1: 484 cm2
Option 2: 482 cm2
Option 3: 488 cm2
Option 4: 486 cm2
Correct Answer: 486 cm2
Solution : Given: The volume of a cube = 729 cm³. ⇒ (Side)3 = 729 ⇒ Side = $\sqrt[3]{729}$ ⇒ Side = 9 cm Total surface area of the cube = 6 × (Side)2 = 6 × 92 = 486 cm2
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