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Question : Directions: A paper is folded and cut as shown below. How will it appear when unfolded?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the given folded paper is unfolded, it will look like –
Hence, the second option is correct.
Question : Select the option that expresses the given sentence in active voice. Were you sent a summons by the court?
Option 1: Has the court sent you a summons?
Option 2: Did the court send you a summons?
Option 3: Will the court send you a summons?
Option 4: Is the court sending you summons?
Correct Answer: Did the court send you a summons?
Solution : The correct choice is the second option.
The active voice, in a sentence, denotes that the noun or pronoun that acts as the subject in the sentence is the doer of the action. In other words, the subject performs
Question : The use of more labour and capital inputs on the given land under cultivation is referred to as
Option 1: extensive cultivation
Option 2: intensive cultivation
Option 3: hybrid cultivation
Option 4: capitalist cultivation
Correct Answer: intensive cultivation
Solution : The correct option is intensive cultivation.
Intensive farming requires significant financial and labour inputs about the size of the farmland. Producing as much food as possible in proportionate amounts is intensive agriculture's goal. Wheat, rice, soyabeans, and corn are intensively grown crops.
Question : Swati sold a bag to Ankita at a gain of 15%. Aashi bought this bag from Ankita for Rs. 24,840. Ankita earned a profit of 20%. At what price would Swati have bought the bag?
Option 1: Rs. 18,500
Option 2: Rs. 18,000
Option 3: Rs. 16,000
Option 4: Rs. 20,000
Correct Answer: Rs. 18,000
Solution : Let the price Swati bought the bag be $x$. According to the question, $x×\frac{100+15}{100}×\frac{100+20}{100}=24840$ $⇒x×\frac{115}{100}×\frac{120}{100}=24840$ $\therefore x =18000$ Hence, the correct answer is Rs. 18,000.
Question : Refer to the data table and answer the following question.
How many students have scored marks 20 or more but less than 40?
Option 1: 31
Option 2: 56
Option 3: 44
Option 4: 100
Correct Answer: 31
Solution : The number of students with a score of at least 40 = 25 The number of students with a 20 or higher score = 56 The number of students who received a score of 20 or higher but below 40 = 56 – 25 =
Question : If $a^3+3 a^2+3 a=63$, then the value of $a^2+2 a$ is:
Option 1: 22
Option 2: 19
Option 3: 15
Option 4: 8
Correct Answer: 15
Solution : $a^3+3 a^2+3 a=63$ We can factor the left side of the equation by recognizing it as a cube of a binomial, $(a+1)^3=a^3+3a^2+3a+1$ Comparing this with the given equation, we have: $(a+1)^3=63+1$ Taking the cube root of both sides, we get: $a + 1 = \sqrt[3]{64}$
Question : Directions: If MUSTARD is written as 132119201184, how is PROFUSE written in that code?
Option 1: 16815621195
Option 2: 16181562195
Option 3: 16181521195
Option 4: 161815621195
Correct Answer: 161815621195
Solution : Given: MUSTARD ⇒ 132119201184 PROFUSE ⇒ ?
The place value of MUSTARD is –
Thus, MUSTARD is coded as 132119201184.
Similarly, follow the same pattern for PROFUSE –
Question : Directions: In a certain code language, SUN is written as 54 and PUT is written as 57. How is CAT written in that code language?
Option 1: 28
Option 2: 24
Option 3: 52
Option 4: 36
Correct Answer: 24
Solution : Given: SUN is written as 54 and PUT is written as 57.
SUN is written as 54; S→19; U→21; N→14 Add all the place values to get the number→19 + 21 + 14 = 54
PUT is written as 57; P→16; U→21; T→20 Add all
Question : Directions: Four triads of numbers have been given out of which three are alike in some manner and one is different. Select a different one. NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.)
Option 1: 19 – 37 – 73
Option 2: 14 – 29 – 59
Option 3: 23 – 47 – 95
Option 4: 3 – 7 – 15
Correct Answer: 19 – 37 – 73
Solution : Let's check the options –
First option: (19 – 37 – 73)→(19 × 2) + 37 + 2 = 38 + 37 + 2 = 77 ≠ 73 Second option: (14 – 29 – 59)→(14 × 2) + 29 + 2
Question : The value of 32 + 12 × 36 ÷ 4 + 4 – 22 ÷ 11 × 3 is:
Option 1: 142
Option 2: 138
Option 3: 150
Option 4: 130
Correct Answer: 138
Solution : 32 + 12 × 36 ÷ 4 + 4 – 22 ÷ 11 × 3 Applying BODMAS, we get: = 32 + 12 × 9 + 4 - 2 × 3 = 32 + 108 + 4 - 6 = 138 Hence, the correct answer
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