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18 Views

Question : In the sentence identify the segment which contains the grammatical error.

'Plogging' is an international trend, in which someone picking up trash while jogging or brisk walking.

Option 1: in which someone

Option 2: picking up trash

Option 3: 'Plogging' is an international trend

Option 4: while jogging or brisk walking

Team Careers360 25th Jan, 2024

Correct Answer: picking up trash


Solution : The error lies in the second option.

The error lies in the verb tense inconsistency, as the verb is in the present participle form, while the verb "is" in the main clause suggests a need for a simple present tense verb. Thus,

13 Views

Question : Directions: Select the figure that will come next in the following figure series.

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 25th Jan, 2024

Correct Answer:


Solution : According to the given figure series –
Each box is rotated by 90 degrees in an anticlockwise direction.
So, following the above pattern, the required figure will be as follows –


Therefore, the figure in the first option is the required figure. Hence, the first option

13 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".

The police is investigating (1) / for the recent happening (2) / in the area. (3) / No error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 24th Jan, 2024

Correct Answer: (1)


Solution : The error lies in the first part of the sentence.

The word "police" is treated as a plural noun and should be followed by the plural form of the verb "are investigating" as per the subject-verb agreement.

Therefore, the correct sentence is: "The police are

55 Views

Question : Two circles each of radius 36 cm are intersecting each other such that each circle passes through the centre of the other circle. What is the length of the common chord to the two circles?

Option 1: $24 \sqrt{3}$ cm

Option 2: $12 \sqrt{3} $ cm

Option 3: $36 \sqrt{3}$ cm

Option 4: $16 \sqrt{3}$ cm

Team Careers360 24th Jan, 2024

Correct Answer: $36 \sqrt{3}$ cm


Solution :
Given: Two circles each of radius 36 cm intersect each other such that each circle passes through the centre of the other circle.
OO' = OC = 36 cm
⇒ OA = AO' = $\frac{36}{2}=18$ cm (radius)
Using Pythagoras theorem in $\triangle AOC$,

10 Views

Question : If $\frac{x^8+1}{x^4}=14$, then the value of $\frac{x^{12}+1}{x^6}$ is:

Option 1: 16

Option 2: 14

Option 3: 52

Option 4: 64

Team Careers360 25th Jan, 2024

Correct Answer: 52


Solution : $\frac{x^8+1}{x^4}=14$
$⇒x^4+\frac{1}{x^4}=14$
$⇒x^4+\frac{1}{x^4}+2=14+2$
$⇒(x^2+\frac{1}{x^2})^2=(4)^2$
$⇒x^2+\frac{1}{x^2}=4$
Now, $\frac{x^{12}+1}{x^6}$
$=x^6+\frac{1}{x^6}$
$=(x^2)^3+\frac{1}{(x^2)^3}$
$=(x^2+\frac{1}{x^2})^3-3×x^2×\frac{1}{x^2}(x^2+\frac{1}{x^2})$
$=4^3-3(4)$
$=64-12=52$
Hence, the correct answer is 52.

17 Views

Question : _____ won silver at the FIDE World Blitz Chess Championship, becoming the first Indian woman to win a medal at the prestigious event in 2022.

Option 1: Koneru Humpy

Option 2: Vantika Agrawal

Option 3: Bhakti Kulkarni

Option 4: Rameshbabu Vaishali

Team Careers360 24th Jan, 2024

Correct Answer: Koneru Humpy


Solution : The correct option is Koneru Humpy.

In 2022, Koneru Humpy won the silver medal at the FIDE World Blitz Chess Championship, becoming the first Indian woman to win a medal at this prestigious event. Despite Humpy's consistently impressive performance in the entire tournament,

17 Views

Question : If $\left(5 a+\frac{4}{a}-2\right)=13$ and a > 0, what is the value of $(25 a^{2}+\frac{16}{a^{2}})$?

Option 1: 158

Option 2: 157

Option 3: 185

Option 4: 175

Team Careers360 25th Jan, 2024

Correct Answer: 185


Solution : Given, $5a+\frac4a-2=13$
⇒ $5a+\frac4a=13+2$
⇒ $5a+\frac4a=15$
Squaring both sides, we get,
⇒ $(5a+\frac4a)^2=(15)^2$
⇒ $25a^2+\frac{16}{a^2}+2\times 5a\times\frac4a=225$ [As $(a+b)^2=a^2+b^2+2ab$]
⇒ $25a^2+\frac{16}{a^2}+40=225$
⇒ $25a^2+\frac{16}{a^2}=225-40$
⇒ $25a^2+\frac{16}{a^2}=185$
Hence, the correct answer is 185.

15 Views

Question : Directions: In the following question, find the odd letter cluster from the given alternatives.

Option 1: HP

Option 2: CJ

Option 3: FN

Option 4: RZ

Team Careers360 24th Jan, 2024

Correct Answer: CJ


Solution : Let's check the options –
First option: HP; H + 8 = P
Second option: CJ; C + 7 = J
Third option: FN; F + 8 = N
Fourth option: RZ; R + 8 = Z

So, the second option is different from the

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