It's a Question of your Career!

For most of the colleges in town (like Maharashtra), the cut-off ranges between

80–85% for Arts, and

75–85% for Commerce and Science.

The third list usually closes down at 70–80%.

It may vary according to caste category.

If you get lucky, some seats are left vacant in a few colleges

For most of the colleges in town, the cut-off ranges between

75–80% for Arts, and

70–75% for Commerce and Science.

The third list usually closes down at 65–70%.

It may vary according to caste category.

If you get lucky, some seats are left vacant in a few colleges after the

Hello aspirant,

For most of the colleges in town(like Maharashtra), the cut-off ranges between

75–80% for Arts, and

70–75% for Commerce and Science.

The third list usually closes down at 65–70%.

It may vary according to caste category.

If you get lucky, some seats are left vacant in a few

Hi,

Bachelors of Mass Media or BMM is an undergraduate course. To be eligible for the course, you will have to clear class 12th in any stream. Along with that, you must have minimum 50% in 10+2 or equivalent examination. This minimum percentage of marks may vary depending on the

Hello,

IPU CET means Indraprastha University Common Entrance Test. This test is Conducted by Indraprastha University authority to offer Admission into various colleges of Indraprastha University.

Army College of Medical College is a Medical College in New Delhi. You must appear for NEET UG in order to take admission into

Hello,

You didn't mention above that in which course you are completed diploma degree. So many diploma courses are available now. Diploma in optometry, diploma in engineering, diploma in pharmacy etc.

If you complete you diploma in engineering or pharmacy then I'll suggest you go for lateral entry admission and

• Hi Akanksha.!

• Any Medical Specialization course Like MBBS or any Specialization like Nursing and other

See as you are seeking admission on the basis of 10+2 results then you should furnish the School Leaving certificate of class 12. But as you didn't have, I would recommend you to get a attested copy from Gazetted Officer which says that you have appeared in the 10+2 examination

Dear aspirant,

For this question you just simply need to apply the formula for torque which is r×F where r = (3-0)i +(2-0)j+(3-0)k and F=(2i-3j+4k) , just do the normal cross product calculations which will give you 17i -6j-13k. This is your final torque expression.